4 pieces of A4 fit on one piece of A2.
4 roughly
A4*2 = A3 A3*2 = A2 = 2*2*A4 A2*2 = A1 = 2*2*2*A4 = 8*A4 Answer: 8 pieces of A4 zized papers will fit on 1 sheet of A1.
Here a1 = -6, a2 = -1, a3 = 4 & a4 = 9 d = a2-a1 = -1-(-6) = -1+6 = 5 d = a3-a2 = 4-(-1) = 4+1 = 5 d = a4-a3 = 9-4 = 5 Therefore the common difference d = 5
(a^2 + 8b)(a^2 - 5b)
(a2+2b2-2ab)(a2+2b2+2ab)
While there are many ways of doing it, the simplest way is to use the SUM function and a range in it like this: =SUM(A1:A5)
Excel formulas that will find the average of cells A1, A2, and A4 are: =AVERAGE(A1 ,A2, A4) or =AVERAGE(A1:A2, A4)
4 pieces of A4 fit on one piece of A2.
an a2 has 6 pieces of a4
A2 is the biggest then A4 then A1
Usually simple substitutions enable such expressions to be seen as quadratic expressions. The substitutions x = a2 and y = b2 give a4 + b4 - 7a2b2 = x2 - 7xy + y2 which does not have any rational factors. Consequently, the quartic in a and b does not have rational factors.
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4 roughly
A4*2 = A3 A3*2 = A2 = 2*2*A4 A2*2 = A1 = 2*2*2*A4 = 8*A4 Answer: 8 pieces of A4 zized papers will fit on 1 sheet of A1.
At most n-1. However, it can be a lot fewer. For example, calculating A10 does not require 9 multiplications. A*A = A2 A2*A2 = A4 A4*A4 = A8 A8*A2 = A10 Only 4 multiplications were required.
If you mean a2 x a2... the answer is a4