0
Want this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
What is the perpendicular bisector equation of the line joined by the points of s 2s and 3s 8s?
Points: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular equation: y-5s = -1/3(x-2s) => 3y-15s = -x+2s => 3y = -x+17s Perpendicular bisector equation in its general form: x+3y-17s = 0
How do you determine the equation for the perpendicular bisector of the straight line joining the points s 2s and 3s 8s?
A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s
Are all multiples of 10 and 12 multiples of 5?
NO besause 5s multiples are only numbers that end with 0 and 5s so no.....!!!
What is the perpendicular bisector equation joining the points of s 2s and 3s 8s on the Cartesian plane showing work?
Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0
What is the perpendicular bisector equation of a line joined by the points of s 2s and 3s 8s showing key stages of work?
It is found as follows:- Points: (s, 2s) and (3s, 8s) Slope: (2s-8s)/(s-3s) = -6s/-2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) Multiply all terms by 3: 3y-15s = -1(x-2s) => 3y = -x+17s In its general form: x+3y-17s = 0
How do you complete the factoring of 25s2-15s equals?
It is: 5s(5s-3)
The perimeter of a square with the length of 15 feet is equal to the perimeter of a regular pentagon What is the length of one side of the pentagon in yards?
A regular pentagon has a perimeter of 5s. We set this equal to 15, and solve for s, and convert to yards.5s = 15s = 33 feet converted to yards is 3/3 = 1 yard.
What is the answer -6s plus 10 equals -5s?
-6s+10 = -5s 5s-6s = -10 -s = -10 s = 10
How do you use the elimination method to solve 3r-5s equals -16 and 5r plus 3s equals 64?
3(3r-5s = -16) 5(5r+3s = 64) Multiply all terms in the first equation by 3 and in the second equation by 5: 9r-15s = -48 25r+15s = 320 Add the equations together in order to eliminate s: 34r = 272 Divide both sides by 34 to find the value of r: r = 8 Substitute the value of r into the original equations to find the value of s: Therefore: r = 8 and s = 8
What does 4 equals 3 over 5s equal?
If: 4 = 3/5s Then: s = 3/20
What is 5s-3 when s equals 5?
22 5s - 3 = 5(5) - 3 = 25-3 = 22
5s-3 equals 3s-9 what does s equal?
5s - 3 = 3s - 92s = -6s = -3
How many 5s are in 40?
10
What is the perpendicular bisector equation of the line joined by the points of s 2s and 3s 8s?
Points: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular equation: y-5s = -1/3(x-2s) => 3y-15s = -x+2s => 3y = -x+17s Perpendicular bisector equation in its general form: x+3y-17s = 0
What is 15s-15?
15s-15 = 0
How do you determine the equation for the perpendicular bisector of the straight line joining the points s 2s and 3s 8s?
A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s
In math what are landmarks?
well landmarks in math are main #'s. like 5s, 10s, 15s, 20s, 25s, 30s, 35s, 40s, 45s, 50s, 55s, 60s, and so on and so on forever and ever.
