Points: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular equation: y-5s = -1/3(x-2s) => 3y-15s = -x+2s => 3y = -x+17s Perpendicular bisector equation in its general form: x+3y-17s = 0
A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s
NO besause 5s multiples are only numbers that end with 0 and 5s so no.....!!!
Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0
Because 12/15 divided by 3/3 = 4/5.
It is: 5s(5s-3)
A regular pentagon has a perimeter of 5s. We set this equal to 15, and solve for s, and convert to yards.5s = 15s = 33 feet converted to yards is 3/3 = 1 yard.
-6s+10 = -5s 5s-6s = -10 -s = -10 s = 10
3(3r-5s = -16) 5(5r+3s = 64) Multiply all terms in the first equation by 3 and in the second equation by 5: 9r-15s = -48 25r+15s = 320 Add the equations together in order to eliminate s: 34r = 272 Divide both sides by 34 to find the value of r: r = 8 Substitute the value of r into the original equations to find the value of s: Therefore: r = 8 and s = 8
If: 4 = 3/5s Then: s = 3/20
22 5s - 3 = 5(5) - 3 = 25-3 = 22
5s - 3 = 3s - 92s = -6s = -3
10
Points: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular equation: y-5s = -1/3(x-2s) => 3y-15s = -x+2s => 3y = -x+17s Perpendicular bisector equation in its general form: x+3y-17s = 0
15s-15 = 0
A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s
well landmarks in math are main #'s. like 5s, 10s, 15s, 20s, 25s, 30s, 35s, 40s, 45s, 50s, 55s, 60s, and so on and so on forever and ever.