3 vertices in a triangle
(t+3)3 is already factored. Could write it as (t+3)(t+3)(t+3).
The answer for ( t + (-3) = 8 ) can be found by adding 3 to both sides of the equation to isolate the variable t. This results in ( t = 11 ), as the negative 3 and positive 3 cancel out, leaving t equal to 8 plus 3. Therefore, the solution for the equation is t equals 11.
t^4 - 81 = (t^2)^2 - (3^2)^2 = (t^2 - 3^2)(t^2 + 3^2) = (t - 3)(t + 3)(t^2 + 9)
2t+8-t=-3(t+t)+8-t=-3-8 -8(t+t)-t=-11the -t and the +t cancel outt=-112(-11)+8-(-11)=-3-22+8+11=-3
-77
The answer to the question "3T in a T" is "3 Trillion in a Terabyte." In digital storage nomenclature, a terabyte (TB) is a unit of information equal to approximately 1 trillion bytes. Therefore, 3T in a T signifies 3 trillion bytes in a terabyte.
3 angles on a triangle.
T over 3 could mean T divided my 3
3 = Teaspoons in a Tablespoon
Subtract 21 from both sides. If that's + 4t, the answer is (t - 3)(t + 7) and t = 3, -7 If that's - 4t, the answer is (t + 3)(t - 7) and t = -3, 7
(39 + t)/3 = 14 Therefore, t = (3 x 14) - 39 t = 3
I am going to guess that you mean: Find t when (√(t + 12)) - t = 0. Then, √(t + 12) = t; t + 12 = t²; (squaring both sides) t² - t - 12 = 0; (t - 4)(t + 3) = 0; and t = 4 or -3. We'd best check both results, because we squared both sides at an earlier stage, which introduces an ambiguity and, probably, an extraneous answer: Our original equation is seen to hold, for t = 4: √(4 + 12)) - 4 = √16 - 4 = 4 - 4 = 0. However, it does not hold, for t = -3. √(-3 + 12)) + 3 = √9 + 3 = 3 + 3 = 6 ≠ 0. Thus, the answer is that t = 4.