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How do you factor m²-4mn-12n²?
(m + 2n)(m - 6n)
How do you factor this polynomial m2-4mn-12n2?
(m - 6n)(m + 2n)
WHY IS AN ODD NUMBER TIMES AN EVEN NUMBER EVEN?
Suppose m and n are integers. Then 2m+1 is an odd number and 2n is an even number.(2m + 1) * 2n = 4mn + 2n = 2*(2mn + 1). Since m and n are integers, the closure of the set of integers under multiplication and addition implies that 2mn + 1 is an integer. Thus the product is a multiple of 2: that is, it is even.
Why is an odd number times an odd number an odd number?
Suppose m and n are integers. Then 2m + 1 and 2n +1 are odd integers.(2m + 1)*(2n + 1) = 4mn + 2m + 2n + 1 = 2*(2mn + m + n) + 1 Since m and n are integers, the closure of the set of integers under multiplication and addition implies that 2mn + m + n is an integer - say k. Then the product is 2k + 1 where k is an integer. That is, the product is an odd number.
Two finite sets have m and n elements If A has 56 more subsets than B then what are the values of m and n?
It's clear that the first set has 2m subsets and second one has 2n subests. so we have to solve 2m - 2n = 56 (m,n are positive integers) Its also clear that m>n let m = k+n so 2k+n- 2n= 56 2n(2k- 1)= 23*7 clearly 2k-1 is odd so 2n= 23, and n = 3 and 2k-1= 7 so k =3 so m = 3+3 = 6 and n = 3
How do you factor m²-4mn-12n²?
(m + 2n)(m - 6n)
How do you factor m squared minus 4mn minus 12n squared?
m2 - 4mn - 12n2 = m2 - 6mn + 2mn - 12n2 = m(m - 6n) + 2n(m - 6n) = (m + 2n)(m - 6n)
How do you factor this polynomial m2-4mn-12n2?
(m - 6n)(m + 2n)
What are the factors of 4mn?
They are 1, 2, 4, m, 2m, 4m, n, 2n, 4n, mn, 2mn and 4mn.
WHY IS AN ODD NUMBER TIMES AN EVEN NUMBER EVEN?
Suppose m and n are integers. Then 2m+1 is an odd number and 2n is an even number.(2m + 1) * 2n = 4mn + 2n = 2*(2mn + 1). Since m and n are integers, the closure of the set of integers under multiplication and addition implies that 2mn + 1 is an integer. Thus the product is a multiple of 2: that is, it is even.
Why is an odd number times an odd number an odd number?
Suppose m and n are integers. Then 2m + 1 and 2n +1 are odd integers.(2m + 1)*(2n + 1) = 4mn + 2m + 2n + 1 = 2*(2mn + m + n) + 1 Since m and n are integers, the closure of the set of integers under multiplication and addition implies that 2mn + m + n is an integer - say k. Then the product is 2k + 1 where k is an integer. That is, the product is an odd number.
What is 2n plus 4m -2n plus m?
2n + 4m - 2n + m = 5m
Why do you get an odd number when you multiply two odd numbers?
Let one odd number be "2m + 1", the other odd number "2n + 1" (where "m" and "n" are integers). All odd numbers have this form. If you multiply this out, you get (2m+1)(2n+1) = 4mn + 2m + 2n + 1. Since each of the first three parts is even, the "+1" at the ends converts the result into an odd number.
2m - n - m - 2n?
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Two finite sets have m and n elements If A has 56 more subsets than B then what are the values of m and n?
It's clear that the first set has 2m subsets and second one has 2n subests. so we have to solve 2m - 2n = 56 (m,n are positive integers) Its also clear that m>n let m = k+n so 2k+n- 2n= 56 2n(2k- 1)= 23*7 clearly 2k-1 is odd so 2n= 23, and n = 3 and 2k-1= 7 so k =3 so m = 3+3 = 6 and n = 3
What does (2n)3 equal in properties of exponents.?
2n x 2n x 2n = 8n^3
Solve by the substitution method 5m plus n equals 37 m-2n equals 14?
5m+n = 37 m-2n = 14 => m = 2n+14 Substitute the value of m into the top equation: 5(2n+14)+n = 37 10n+70+n = 37 10n+n = 37-70 11n = -33 Divide both sides by 11 to find the value of n: n = -3 Substitute the value of n into the original equations to find the value of m: Therefore: n = -3 and m = 8
