0
(4x)3 = 64x3
y0 = 1
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What is the y-intercept of y equals 4x?
zero x-intercept also zero
State the y-intercept for the graph y equals -4x?
y = -4x The y-intercept is zero. That is, the graph passes through the origin.
How do you show 4x equals y?
4x = y : or it can be written in the reverse order, y = 4x.
Standard form of y -4x-1?
-3
What is the measure of the third side of a triangle where the perimeter is 8X plus 4Y and the others are X plus 2Y and 3X plus Y?
The perimeter of the triangle is 8x + 4y. The measures of two of the sides are x + 2y and 3x + y. If these two sides were added together, they would be 4x + 3y:x + 2y3x + y4x + 3yThe third side is the perimeter minus the two known sides, so 8x + 4y - (4x + 3y). Distribute the negative: 8x + 4y - 4x - 3y. This is equal to the third side, which is 4x +y.
What is the y-intercept of y equals 4x?
zero x-intercept also zero
State the y-intercept for the graph y equals -4x?
y = -4x The y-intercept is zero. That is, the graph passes through the origin.
What are the intercepts for the line -4x plus y equals 8?
-4x + y = 8At the x-intercept, 'y' is zero.-4x = 8-x = 2x = -2At the y-intercept, 'x' is zero.y = 8
What are the intercepts of -4x plus 6y-5z equals 60?
-4x + 6y - 5z = 60At the x-intercept, 'y' and 'z' are zero:-4x = 60 ===> x = -15At the y-intercept, 'x' and 'z' are zero:6y = 60 ===> y = 10At the z-intercept, 'x' and 'y' are zero:-5z = 60 ===> z = -12
What is 8 plus y equals 4x in standard form?
8 + y = 4x8 + y - 4x = 4x - 4x 8 + y - 4x = 0 8 - 4x + y = 0
Find the x and y-intercepts y equals 4x-14?
18
Find the slope of 4x 3y-120?
If you meant 4x=3y-120 ==> 4x +120 = 3y ==> 4/3x+40=y In y=4/3x+40 4/3 is the slope (y will be increased by 4 when x is increased of 3) and +40 is the y intercept (when x is zero y is +40)
What is the vertex of the parabola y-2x2-4x 4?
Assuming the missing symbol there is an equals sign, then we have: y - 2x2 - 4x = 4 We can find it's vertex very easily by solving for y, and finding where it's derivative equals zero: y = 2x2 + 4x + 4 y' = 4x + 4 0 = 4x + 4 x = -1 So the vertex occurs Where x = -1. Now we can plug that back into the original equation to find y: y = 2x2 + 4x + 4 y = 2 - 4 + 4 y = 2 So the vertex is at the point (-1, 2)
What is the minimum of y equals 2x²-7x-2?
First take the derivative: y' = 4x - 7 Now, solve for derivate equals zero: 4x - 7 = 0 4x = 7 x = 7/4 Locations where the derivative is zero may be a minimum, or a maximum, or neither (in this case it is indeed a minimum). Finally calculate the value of y for this particular value of x.
How do you show 4x equals y?
4x = y : or it can be written in the reverse order, y = 4x.
How do you solve the square root of 4x to the sixth power?
4x to the sixth can be expanded to (4x * 4x * 4x)(4x * 4x * 4x) or (4x to the third)(4x to the third) the square root of the above would be 4x to the third
How would you solve for y in this problem 4x plus y equals 8?
You cannot solve one linear equation in two variables. You can express y in terms of x but that is NOT solving for y.
