-8x+3y=12 3y = 8x+12 y = (8/3)x + 4 So it will be a line with slope 8/3 and y intercept of 4
x+7x+3y-y =8x+2y =2(4x+y)
6x - 3y + 2 = -3y - 2x8x + 2 = 0 (add 3x + 2y to both sides)8x = -2 (subtract 2 from both sides)x = -1/4 or -0.25 (divide both sides by 8)
If that's -8x, the answer is (x - 4)(x - 4) or (x - 4)2 If that's +8x, the answer is (x + 4)(x + 4) or (x + 4)2
8x + 3y = 248x - 8x + 3y = -8x + 243y = - 8x + 243y/3 = (- 8x + 24)/3y = -8x/3 + 24/3y = (-8/3)x + 8 this is the slope-intercept form of the equation of the line, y = mx + b, where the slope m is -8/3 and the y-intercept b is 8.
x² + 8x -2 = 0 x² + 8x = 2 x² + 8x + (8/2)² = 2 + (8/2)² x² + 8x + 16 = 2 + 16 (x + 4)² = 18 x + 4 = ±√18 x = -4 ±√18 x = -4 + √18 or x = -4 - √18 if you are still confused, i want you to follow the related link that explains the concept of completing the square clearly.
A system? Try elimination 3(8X - Y = 4) 5X + 3Y = 17 24X - 3Y = 12 5X + 3Y = 17 -------------------------+ 29X = 29 X = 1 -----------find Y 8(1) - Y = 4 - Y = - 4 Y = - 1 -----------check By inspection one can see this is inconsitent
x*x - 8x +16 = 0 x*x = 8x + 16 x - 16 = _/8x x_/-4 = 2 x = 2
3y + 18 = -8x + 3Subtract 18 from each side:3y = -8x - 15Divide each side by 3:y = (-8/3)x - 5
x2 - 8x - 40 = 0 ∴ x2 - 8x = 40 ∴ x2 - 8x + 16 = 56 ∴ (x - 4)2 = 56 ∴ x - 4 = ± 561/2 ∴ x = 4 ± 561/2 ∴ x = 4 ± 2 × 141/2 ∴ x ≈ {11.4833, -3.4833}
The expression X-4 x X-4 simplifies to X^2 - 8X + 16.
2x2 = 8x x = 8x/2x x = 4 Check: 2(4)2 = 8(4) 2(16) = 32 32 = 32