you can not solve this equation
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
3y + 2y + 4 + 1 = 805y + 5 = 805y = 75y = 15
You cannot solve one linear equation in two unknown variables.
If you mean: 80 = 3y+2y+4+1 then 80 =5y+5 and so y = 15
you can not solve this equation
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
If you mean: 11x+2y = 34 then y = -10.5x+17 whereas -10.5 is the slope and 17 is the y intercept of a straight line equation
There are two expressions in the question but no equation - so nothing to solve.
If you mean: 3x+2y+6 = 0 then it is y = -1.5x-3 as a straight line equation
3y + 2y + 4 + 1 = 805y + 5 = 805y = 75y = 15
You cannot solve one linear equation in two unknown variables.
No. There is not enough information in the equation x + 2y = 2, by itself, to solve it. There are an infinite number of solutions. A second equation, or information to allow a second equation to be derived, must be given to find a solution.
If you mean: 80 = 3y+2y+4+1 then 80 =5y+5 and so y = 15
x + 52 + 2y + 35 = 3 x + 2y = 3 - 52 -35 x + 2y = -84 Infinite number of solutions, are you sure you posted the correct equation?
This is a system of two linear equations: x+2y=11 3x-4y=-17 One way to solve this system is to solve for x (or y) in the first equation and then plug it into the second equation to solve for the other variable, which then allows us to solve for our original variable. (1) Take the first equation and solve for x: x=11-2y (2) Plug this value into the second equation: 3x-4y=3(11-2y)-4y=33-10y=-17. We see that y=5. (3) We now plug this into either equation to solve for x: From (1): x=11-2y=11-2(5)=1 We get x=1 and y=5. It's also always a good idea to plug the numbers we found into our original two equations to verify they work. Indeed, x+2y=1+2(5)=1+10=11, and 3x-4y=3(1)-4(5)=3-20=-17.
Without an equality sign and not knowing the plus or minus values of 7y and 2y the expression given can't be considered to be an equation