9 - n 12 = -3
3 + 9 = 12
If you mean: -3(n+5) = 12 then n works out as -9 because -3(-9+5) = 12
9/12 = 15/20
-3
5/(n - 12) = 10(n + 5) (multiply by the common denominator (n - 120(n + 9) to both sides)[5/(n - 12)][(n - 12)(n + 9)] = [10(n + 5)][(n - 120)(n + 9)] (simplify)5(n + 9) = 10(n - 12)5n + 45 = 10n - 120 (subtract 5n and add 120 to both sides)5n - 5n + 120 + 45 = 10n - 5n + 120 - 120165 = 5n (divide by 5 to both sides)33 = n
6n -3=2n+9 6n-2n=9+3 4n=12 n=12/4 n=3
12 x 9 = 108
7*n-n 7*2-2=12 9*2-2=16
There is a choice of 12 for the first, leaving 11 for the second, leaving 10 for the third, and so on, leaving 4 for the last, a total of 12 × 11 × 10 × ... × 4 = 79,833,600 ways. ------------------------------------------------------ This is a mathematical "permutation" which is a selection of r items from a total of n items where the order of selection matters. It can be calculated by using the formula: nPr = n!/(n-r)! Where n! is n factorial which is calculated as n × (n-1) × (n-2) × ... 1 0! is defined to be: 0! = 1. In this case 12P9 = 12!/(12-9)! = 12!/3! = (12 × 10 × 9 × ... × 4 × 3 × 2 × 1)/(3 × 2 × 1) = 12 × 10 × 9 × ... × 4 = 79,833,600 as before.
If the question is, "What is the solution to 2n2 + 6n - 108 = 0 ?"The equation can be factored : 2n2 + 6n - 108 = (2n - 12)(n + 9) = 0If 2n -12 = 0 then n = 6If n + 9 = 0 then n = -9The roots of this equation are n = 6 and n = -9.
A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.
# of possible square shapes viewed in a n x n grid# of squares = (n)2 + (n-1)2 + (n-2)2 ... (1)2Examples:When n=1: 12 = 1When n=2: 22 + 12 = 5When n=3: 32 + 22 + 12 = 9 + 4 + 1 = 14When n=4: 42 + 32 + 22 +12 = 16 + 9 + 4 + 1 = 30