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9 - n 12 = -3
What else can I help you with?
What is n plus 9 when n equals 3?
3 + 9 = 12
-3(n plus 5)12?
If you mean: -3(n+5) = 12 then n works out as -9 because -3(-9+5) = 12
What is the answer to 9 12 equals n 20?
9/12 = 15/20
Five divided by the difference of a number and 12 equals the quotient of 10 and the sum of the number and 9?
5/(n - 12) = 10(n + 5) (multiply by the common denominator (n - 120(n + 9) to both sides)[5/(n - 12)][(n - 12)(n + 9)] = [10(n + 5)][(n - 120)(n + 9)] (simplify)5(n + 9) = 10(n - 12)5n + 45 = 10n - 120 (subtract 5n and add 120 to both sides)5n - 5n + 120 + 45 = 10n - 5n + 120 - 120165 = 5n (divide by 5 to both sides)33 = n
What is -12 - -9?
-3
What is 6n-3 equals 2n plus 9?
6n -3=2n+9 6n-2n=9+3 4n=12 n=12/4 n=3
How many different teams of 9 can be chosen from 12 students?
To determine how many different teams of 9 can be chosen from 12 students, we use the combination formula (C(n, k) = \frac{n!}{k!(n-k)!}), where (n) is the total number of students and (k) is the number of students to choose. Here, (n = 12) and (k = 9). Thus, the calculation is (C(12, 9) = C(12, 3) = \frac{12!}{3! \cdot 9!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220). Therefore, there are 220 different teams of 9 that can be chosen from 12 students.
Evaluate 12n if n 9?
12 x 9 = 108
How many different batting orders can be made with 12 players of a softball team competing for 9 spots?
There is a choice of 12 for the first, leaving 11 for the second, leaving 10 for the third, and so on, leaving 4 for the last, a total of 12 × 11 × 10 × ... × 4 = 79,833,600 ways. ------------------------------------------------------ This is a mathematical "permutation" which is a selection of r items from a total of n items where the order of selection matters. It can be calculated by using the formula: nPr = n!/(n-r)! Where n! is n factorial which is calculated as n × (n-1) × (n-2) × ... 1 0! is defined to be: 0! = 1. In this case 12P9 = 12!/(12-9)! = 12!/3! = (12 × 10 × 9 × ... × 4 × 3 × 2 × 1)/(3 × 2 × 1) = 12 × 10 × 9 × ... × 4 = 79,833,600 as before.
How many different 9-member teams can be chosen from 12 students?
To determine how many different 9-member teams can be chosen from 12 students, we can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). Here, ( n = 12 ) and ( k = 9 ). This can also be expressed as ( C(12, 9) = C(12, 3) ), which simplifies the calculation. Thus, ( C(12, 3) = \frac{12!}{3! \cdot 9!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220 ). Therefore, there are 220 different 9-member teams that can be formed.
Find the missing number in the ratio 7 to 12 equals x to 9?
7*n-n 7*2-2=12 9*2-2=16
What is 2n squared plus 6n mines 108?
If the question is, "What is the solution to 2n2 + 6n - 108 = 0 ?"The equation can be factored : 2n2 + 6n - 108 = (2n - 12)(n + 9) = 0If 2n -12 = 0 then n = 6If n + 9 = 0 then n = -9The roots of this equation are n = 6 and n = -9.
