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How many different batting orders can be made with 12 players of a softball team competing for 9 spots?
Wiki User
∙ 7y ago
There is a choice of 12 for the first, leaving
11 for the second, leaving
10 for the third, and so on, leaving
4 for the last, a total of 12 × 11 × 10 × ... × 4 = 79,833,600 ways.
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This is a mathematical "permutation" which is a selection of r items from a total of n items where the order of selection matters. It can be calculated by using the formula:
nPr = n!/(n-r)!
Where n! is n factorial which is calculated as n × (n-1) × (n-2) × ... 1
0! is defined to be: 0! = 1.
In this case 12P9 = 12!/(12-9)! = 12!/3! = (12 × 10 × 9 × ... × 4 × 3 × 2 × 1)/(3 × 2 × 1) = 12 × 10 × 9 × ... × 4 = 79,833,600 as before.
Wiki User
∙ 7y ago
Wiki User
∙ 7y ago9 spots from 12 players can be selected in 79,833,600 ways.
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Example of permutation?
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