It is unusual to do arithmetic in Roman numerals, but I x V is the same as 1 x 5 which is of course 5.
(c/x) /v = (c/x) * (1/v) = c/(x*v), so c divided by (the product of x and v).
4 x V¯6 ---------- V¯30 Simplify V¯6 to V¯3 and V¯2; Simplify V¯30 to V¯10 and V¯3 4 x V¯3 x V¯2 ------------------- V¯10 x V¯3 Simplify V¯10 to V¯5 and V¯2 4 x V¯3 x V¯2 ---------------------- V¯5 x V¯2x V¯3 Cross out V¯3 and V¯2 from both sides. 4 ------- V¯5 Multiply the numerator and denominator by V¯5 (You cannot have a radical in the denominator). 4 x V¯5 --------- <---- Final Answer 5
v + x
There is no "you" in P = V x I
x = W2 - V and you cannot get any further than that since neither W nor V are known.
(c/x) /v = (c/x) * (1/v) = c/(x*v), so c divided by (the product of x and v).
v= lwh v=x(x)(x) or v= x3.( cubed) exponential
4 x V¯6 ---------- V¯30 Simplify V¯6 to V¯3 and V¯2; Simplify V¯30 to V¯10 and V¯3 4 x V¯3 x V¯2 ------------------- V¯10 x V¯3 Simplify V¯10 to V¯5 and V¯2 4 x V¯3 x V¯2 ---------------------- V¯5 x V¯2x V¯3 Cross out V¯3 and V¯2 from both sides. 4 ------- V¯5 Multiply the numerator and denominator by V¯5 (You cannot have a radical in the denominator). 4 x V¯5 --------- <---- Final Answer 5
v + x
KE = (0.5) x mass x V x V [at velocity V] KE = (0.5) x mass x (0.5V) x (0.5V) [at velocity 0.5V] Ratio = [0.5 x mass x V x V] / [0.5 x mass x 0.25 x V x V] = [1] / [0.25] = 4 This means that the KE will be 1/4 at half the speed compared to KE at the original speed
x/r=v x=vr
There is no "you" in P = V x I
V Vulture X X-Ray Tetra (fish)
The letter W is between V and X.
Kinetic energy at velocity "V" is (0.5) x mass x V x V Kinetic energy at velocity "2V" is (0.5) x mass x 2V x 2V Ratio of KE at velocity 2V and KE at velocity V is [(0.5) x mass x 2V x 2V] / [(0.5) x mass x V x V] = 4 So if the velocity double, KE quadruples
V=r x pi x h V= 70 x 3.14 x 50 V=10990cm³ or 11L
x = W2 - V and you cannot get any further than that since neither W nor V are known.