answersLogoWhite

0


Best Answer

It is unusual to do arithmetic in Roman numerals, but I x V is the same as 1 x 5 which is of course 5.

User Avatar

Wiki User

11y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is I x V?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What do you get if you divide c by x and then divide result by v?

(c/x) /v = (c/x) * (1/v) = c/(x*v), so c divided by (the product of x and v).


What is the volume of a cube with an edge x inches long?

v= lwh v=x(x)(x) or v= x3.( cubed) exponential


Simplify 4 square root of 6 divided by square root of 30 reduce first?

4 x V¯6 ---------- V¯30 Simplify V¯6 to V¯3 and V¯2; Simplify V¯30 to V¯10 and V¯3 4 x V¯3 x V¯2 ------------------- V¯10 x V¯3 Simplify V¯10 to V¯5 and V¯2 4 x V¯3 x V¯2 ---------------------- V¯5 x V¯2x V¯3 Cross out V¯3 and V¯2 from both sides. 4 ------- V¯5 Multiply the numerator and denominator by V¯5 (You cannot have a radical in the denominator). 4 x V¯5 --------- <---- Final Answer 5


If 5 is v 10 is x what is 15?

v + x


How do you solve x divided by r equals v for x?

x/r=v x=vr


What does the you stand for P equals V x I?

There is no "you" in P = V x I


What animal begins with v or x?

V Vulture X X-Ray Tetra (fish)


What letter is between V and X?

The letter W is between V and X.


If you have a cylinder with radius 70cm and height 50 cm what is the volume?

V=r x pi x h V= 70 x 3.14 x 50 V=10990cm³ or 11L


What is V plus x equals Wsquared what is x?

x = W2 - V and you cannot get any further than that since neither W nor V are known.


Radio Antennas work best when the diameter of the antenna is equal to the wavelength of its radio wave Reasonable antennas range from 1 cm-5 m in diameter What frequency range fits the antenna range?

1 cm= .01 m C=?v 3.00 x 108 m/s= .01 m (v) v= 3.00 x 1010 Hz C=?v 3.00 x 108 m/s= 5 m (v) v= 6.00 x 107 Hz Frequency range: 3.00 x 1010 Hz - 3.00 x 107 Hz


Xsquared - v equals wsquared what is X how did you work this out?

It is not possible to solve for a value of X since there are three unknowns, X, v and W and only one equation. All that can be done is to make x the subject of the equation - that is, to express X in terms of the other two variables. X2 - v = W2 X2 = W2 + v X = +/- sqrt(W2 + v)