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The expression ( X - y^2 ) represents the difference between a value ( X ) and the square of another value ( y ). To evaluate this expression, you would first compute ( y^2 ) (which is ( y ) multiplied by itself) and then subtract that result from ( X ). The final answer will depend on the specific values of ( X ) and ( y ).
What else can I help you with?
What is y to the 8th power as an product in four different was with only positive exponents?
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
Is this a function x equals y2?
Yes, as x-y2=0
Convert x2 plus y2 equals 2x?
What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2
What is the answer to y2 x y?
Y3
How do you solve y2-x-6y plus 6 equals 0 as a parabola equation?
y2-x-6y+6=0 y2-6y+6=x (y-3)2-3=x so y = 3+sqrt(x+3) or y = 3-sqrt(x+3)
What is y to the 8th power as an product in four different was with only positive exponents?
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
How do you solve (x y2)(x-y2)?
0
Is this a function x equals y2?
Yes, as x-y2=0
What is the answer to (x plus y)2 x2 plus y2?
X2+y2=25 (x-8)2+y2 =41
Convert x2 plus y2 equals 2x?
What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2
Factorise x2 minus y2 plus 9x minus 9y?
x2 - y2 + 9x - 9y =(x2 + 9x) - (y2 + 9y) =x(x + 9) - y(y + 9)================================Another way to go after it:x2 - y2 + 9x - 9y =(x2 - y2) + 9x - 9y =(x + y) (x - y) + 9 (x - y) =(x + y + 9) (x - y)
How do you factor x2-y2?
x2-y2=(x-y)(x+y) which is a well known identity.
How do you factor 4-y²?
4 - y2 can be written as 22 - y2. This has become of the form of x2 - y2.Expansion for x2 - y2 is (x+y)(x-y).So, 4 - y2 = 22 - y2 = (2+y)(2-y)
How do you factor x6 - y6?
(x - y)(x + y)(x2 - xy + y2)(x2 + xy + y2)
What are the factors of x2 - y4?
-2
What is the result of isolating y2 (x - 2)2 y2 64?
(x-2)^2+y^2=64
Can a graph be symmetrical about the x axis?
X = y2 =====
