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(x-2)^2+y^2=64
Sanford Ankunding
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What is the result of isolating y2 in the equation below (x plus 4) plus y2 22?
y2=-x2-8x+6
What is the result of isolating y2 in the equation below?
(x-2)^2+y^2=64
What is the distance formula in 3D?
The formula: distance=sqrt(((x1-x2)*(x1-x2))+((y1-y2)*(y1-y2))+((z1-z2)*(z1-z2))) In DarkBASIC it's: function distance3D(x1,y1,z1,x2,y2,z2) x=x1-x2 y=y1-y2 z=z1-z2 result=sqrt((x*x)+(y*y)+(z*z)) endfunction result In classic BASIC I think it's: FUNCTION distance3D(x1,y1,z1,x2,y2,z2) x=x1-x2 y=y1-y2 z=z1-z2 result=SQRT((x*x)+(y*y)+(z*z)) RETURN result END FUNCTION
The equation of the inner circle is x2 plus y2 equals 4 the radius of the outer circle is four times the radius of the inner circle write the equation of the outer circle?
The inner circle is x2 + y2 = 4. The radius of the inner circle is the square root of 4, which is 2. To find the radius of the outer circle, multiply 2 times 4. The radius of the outer circle is 8. Square 8 (82 or 8 x 8) to find the number to put into the equation of the outer circle. This is 64. The equation for the outer circle is x2 + y2 = 64.
What is the expansion for x2 plus y2?
There is no expansion for x2 + y2
What is the result of isolating y2 in the equation below (x plus 4) plus y2 22?
y2=-x2-8x+6
What is the result of isolating y2 in the equation below?
(x-2)^2+y^2=64
How do you factor y2-64?
y2 - 64 can be written as y2 - 82, which is of the form of a2 - b2.And a2 - b2 is factored as (a-b)(a+b).Therefore, y2 - 64 is factored as (y+8)(y-8).
The circle is centered at the origin and the length of its radius is 8 What is the circle's equation?
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
How does y2 equals 64?
If y=8, then 8 squared is 64.
What is the y2-16y 64 equals 0?
y2 - 16y + 64 = 0 (y - 8)2 = 0 y - 8 = 0 y = 8
The radius of x2 y2 equals 64?
8
How do you factor 4-y²?
4 - y2 can be written as 22 - y2. This has become of the form of x2 - y2.Expansion for x2 - y2 is (x+y)(x-y).So, 4 - y2 = 22 - y2 = (2+y)(2-y)
If the equation of a circle is x2 y2 64 what is its radius?
8
What is 66-3y plus y2 from 88 plus 5y-y2?
88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
Divide y2 plus 13y plus 22 by y plus 2?
(y2+13y+22)/(y+2) = (y+11)
Which is the equation of the circle with its center at origin and radius 8?
x2 + y2 = 64
