x^2(x - 4)(x + 4)
If you are trying do find out x it's 2. 2 to the fourth power equals sixteen.
It is: (x-y)4
(x2 + 1)(x2 - 2)
(4x - 1)(4x + 1)
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.
3x^4 - 12 = 3(x^4 - 4) = 3(x² + 2)(x² - 2)
x4 - 81 = 0x4 = 81x = 3
5x^2(4x - 5)(5x + 11)
(-9 x -8) + (-16) = (72) -16 = 56
x4 - x3 - x - 1 rewriting: = x4 - 1 - x3 - x factorising pair of terms: =(x2 + 1)*(x2 - 1) - x*(x2 + 1) = (x2 + 1)*(x2 - 1 - x) or (x2 + 1)*(x2 - x - 1) which cannot be factorised further.
x4 - x2 - 12 = (x2 + 3) (x2 - 4)And (x2 - 4) = (x + 2) (x - 2)So the original expression = (x2+ 3) (x + 2) (x - 2)