x4 - x3 - x - 1
rewriting: = x4 - 1 - x3 - x
factorising pair of terms: =(x2 + 1)*(x2 - 1) - x*(x2 + 1)
= (x2 + 1)*(x2 - 1 - x)
or (x2 + 1)*(x2 - x - 1)
which cannot be factorised further.
It is: (x-y)4
(x2 + 1)(x2 - 2)
2x to the fourth power minus 162 equals -146
-16,128
No.
It is: (x-y)4
(x2 + 1)(x2 - 2)
2x to the fourth power minus 162 equals -146
x^2(x - 4)(x + 4)
-16,128
No.
It is +1
x cubed minus 216
(3x^2 - 4y^2)(3x^2 + 4y^2)
So x4 - 1 is the difference of squares, so x4 - 1 = (x2 - 1)(x2 + 1) = (x + 1)(x - 1)(x2 + 1).
-68 I think
(x4 - 16) = (x2 + 4) (x2 - 4) = (x2 + 4) (x + 2) (x - 2)