(a2 + 2a + 1)/(5a + 5)
factor, top and bottom
(a + 1)(a + 1)/5(a + 1)
cancel an (a + 1) top and bottom
= (a + 1)/5
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(a2 + 5a + 6)/(a - 2) = (a + 2)*(a 3)/(a - 2) which cannot be simplified further. It can, however be written as (a2 - 2a + 7a - 14 + 20)/(a - 2) which is (a + 7) + 20/(a - 2)
(a2 + a + a2) = (2a2 + a) = a (2a + 1)
a2 + -5a2 - a2 - a = a2 - 5a2 - a2 - a = a2 - 6a2 - a = -5a2 - a
5a+3a2a2= 8a a2
If I've read your question correctly, you need to subtract: a2 +2a -7 a2 -4a2 +5a2 -6 = 2a2 -6 Note, if x - y = z, then y = x - z; so: 2a2 -6 - (a2 -2a +1) = 2a2 -6 - a2 +2a -1 = a2 +2a -7
a≠ 0,LCD = a33/a + 2/a2 - 1/a3= (3/a)(a2/a2) + (2/a2)(a/a) - 1/a3= 3a2/a3 + 2a/a3- 1/a3= (3a2 + 2a -1)/a3
5a3-45a=-2a2+18 5a(a2-9)=-2(a2-9) 5a=-2 a=-2/5
2A plus 3B times 2A - 3B = 4A2 - 9B2; this is an example of the general formula (a + b)(a - b) = a2 - b2.
(a - 5)(a + 3) = a2 - 2a - 15
a2-5a-14 = (a-7)(a+2) when factored
Not sure why it is 3a2- if you mean 3*a*2, then: 3*a*2=6a (6a-2a)+5-2(a (or a2)+a)=1 4a+5-(2a+a)=1 4a+5-2a-a=1 Then take the 5 over (remember, the +5 become -5 when transposed): 4a-2a-a=1-5 Solving the equations on both sides gives: a=-4 Is this your answer?
a2(2a2-21a+49) a2(2a-7)(a-7)