Multiples of 10 between 1000 and 9990
Any four-digit number ending in zero.
9000
10 is divisible by both 5 and 2, as are any multiples of 10.
Because 10 is divisible by both 2 and 5
60
To find a number that is divisible by both 2458 and 10, we need to find the least common multiple (LCM) of the two numbers. The LCM of 2458 and 10 is the smallest number that is a multiple of both 2458 and 10, which is 24580. Therefore, 24580 is the number that is divisible by both 2458 and 10.
There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
10
It is 90.
A number divisible by both 2 and 5 will be divisible by their product (2 x 5), which is 10. Any number divisible by 10 ends in 0. The only number listed that ends in 0 is 110.
To determine if 610 is divisible by both 6 and 10, we need to check if it is divisible by both 6 and 10 individually. For 6, we check if 610 is divisible by 2 and 3. Since 610 is even but not divisible by 3, it is not divisible by 6. For 10, we check if 610 ends in 0, which it does not. Therefore, 610 is not divisible by 10 either.
60
If a number ends with 0, it is divisible by 10.If a number ends with 0, it is divisible by 10.If a number ends with 0, it is divisible by 10.If a number ends with 0, it is divisible by 10.