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There is no such shape.

A polygon with n (n >2) sides has n*(n-3)/2 diagonals.

Therefore n*(n-3)/2 = 2 implies n^2 - 3n = 4 or n^2 - 3n - 4 = 0

This can be factorised to (n+1)*(n-4) = 0 which implies that n = -1 or n = 4

Now, a polygon cannot have -1 sides and therefore it MUST have 4 sides. That is, it must be a quadrilateral.

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