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What is the negation of the statement quadrilateral abcd is a paralleogram and it has a right angle?
"abcd is not a parallelogram or it does not have any right angles." ~(P and Q) = ~P or ~Q
What is the area of the quadrilateral ABCD whose vertices are at -1 4 and 3 7 and 5 2 and -5 -17 giving the reason for your answer?
When the given vertices are plotted and joined together on the Cartesian plane they will form a 4 sided quadrilateral whose diagonals intercept each other at right angles and so multiplying the lengths of the diagonals divided by two will produce an area of 80 square units.
What are the properties of the diagonals of a rectangle?
A Rectangle is a quadrilateral (four sided polygon) with two pairs of equal and parallel sides (opposite sides are parallel and equal, one pair is usually a different length from the other pair but if they are equal it is called a square), and all angles are right angles (90°). It has two diagonals which have the properties:The diagonals are always congruent (of equal length);The diagonals bisect each other (cut each other into two equal parts);The diagonals do not bisect the angles (unless the rectangle is a square when they do);The diagonals are not perpendicular (unless the rectangle is a square when they do).PROOF of the diagonals congruent:Take a rectangle ABCD with diagonals AC and BD.Using Pythagoras on the triangles ACD and BCD:AC² = AD² + CD²BD² = BC² + CD²But as ABCD is a rectangle AD = BC since they are opposite and parallel; thus:AC² = AD² + CD² = BC² + CD² = BD²Thus, as AC and BD are the diagonals, they are equal.Therefore the diagonals of a rectangle are congruent.
When can this be true abcd is a quadrilateral does a plus b plus c plus d equals 180?
No; it is false. The sum of all the angles of a quadrilateral always equals 360o.
What is the area of the quadrilateral ABCD whose vertices are at -1 4 and 3 7 and 5 2 and -4 -17 respectively on the Cartesian plane?
Its diagonals intersect each other at right angles when plotted on the Cartesian plane Its diagonal lengths are 2 times square root of 10 and 8 times square root of 10 Its area is 0.5 times product of its diagonals equals 80 square units
What is the negation of the statement quadrilateral abcd is a paralleogram and it has a right angle?
"abcd is not a parallelogram or it does not have any right angles." ~(P and Q) = ~P or ~Q
Which quadrilaterals have diagonals that bisects each other?
A quadrilateral whose diagonals bisect each other at right angles is a rhombus. each other at right angles at M. So AB = AD and by the first test above ABCD is a rhombus. 'If the diagonals of a parallelogram are perpendicular, then it is a rhombus
in the figure ab is parallel to DC a)find all linear angles of the quadrilateral ABCD b)find all outer angles of the quadrilateral ABCD?
This is the image
Show that if diagonals of a quadrilateral bisects each other then it is a rhombus?
This cannot be proven, because it is not generally true. If the diagonals of a quadrilateral bisect each other, then it is a parallelogram. And conversely, the diagonals of any parallelogram bisect each other. However not every parallelogram is a rhombus.However, if the diagonals are perpendicular bisectors, then we have a rhombus.Consider quadrilateral ABCD, with diagonals intersecting at X, whereAC and BD are perpendicular;AX=XC;BX=XD.Then angles AXB, BXC, CXD, DXA are all right angles and are congruent.By the ASA theorem, triangles AXB, BXC, CXD and DXA are all congruent.This means that AB=BC=CD=DA.Since the sides of the quadrilateral ABCD are congruent, it is a rhombus.
Quadrilateral ABCD is a parallelogram Which two angles below are supplementary?
a and d
What is the area of the quadrilateral ABCD whose vertices are at -1 4 and 3 7 and 5 2 and -5 -17 giving the reason for your answer?
When the given vertices are plotted and joined together on the Cartesian plane they will form a 4 sided quadrilateral whose diagonals intercept each other at right angles and so multiplying the lengths of the diagonals divided by two will produce an area of 80 square units.
Is the converse of the rectangle diagonals conjecture true?
Converse: If the diagonals of a quadrilateral are congruent and bisect each other, then the quadrilateral is a rectangle. Given: Quadrilateral ABCD with diagonals , . and _ bisect each other Show: ABCD is a rectangle Because the diagonals are congruent and bisect each other, . Using the Vertical Angles Theorem, AEB CED and BEC DEA. So ∆AEB ∆CED and ∆AED ∆CEB by SAS. Using the Isosceles Triangle Theorem and CPCTC, 1 2 5 6, and 3 4 7 8. By the Angle Addition Postulate each angle of the quadrilateral is the sum of two angles, one from each set. For example, mDAB = m1 + m8. By the addition property of equality, m1 m8 m2 m3 m5 m4 m6 m7. So by substitution mDAB mABC mBCD mCDA. Therefore the quadrilateral is equiangular. Using 1 5 and the Converse of AIA, . Using 3 7 and the Converse of AIA, . Therefore ABCD is an equiangular parallelogram, so it is a rectangle by definition of rectangle.
What are the properties of the diagonals of a rectangle?
A Rectangle is a quadrilateral (four sided polygon) with two pairs of equal and parallel sides (opposite sides are parallel and equal, one pair is usually a different length from the other pair but if they are equal it is called a square), and all angles are right angles (90°). It has two diagonals which have the properties:The diagonals are always congruent (of equal length);The diagonals bisect each other (cut each other into two equal parts);The diagonals do not bisect the angles (unless the rectangle is a square when they do);The diagonals are not perpendicular (unless the rectangle is a square when they do).PROOF of the diagonals congruent:Take a rectangle ABCD with diagonals AC and BD.Using Pythagoras on the triangles ACD and BCD:AC² = AD² + CD²BD² = BC² + CD²But as ABCD is a rectangle AD = BC since they are opposite and parallel; thus:AC² = AD² + CD² = BC² + CD² = BD²Thus, as AC and BD are the diagonals, they are equal.Therefore the diagonals of a rectangle are congruent.
Are the diagonals of a rectangle congruent always?
Yes. You can show this by SAS of two right triangles. Consider rectangle ABCD. AD and BC are the same length and AC and BD are the same length because opposite sides are congruent. The angles ADC and BCD are congruent since it is a rectangle and the angles are right angles. So the triangles ADC and BCD are congruent and their hypotenuses (the diagonals of the rectangles) are congruent.
When can this be true abcd is a quadrilateral does a plus b plus c plus d equals 180?
No; it is false. The sum of all the angles of a quadrilateral always equals 360o.
What is the area of the quadrilateral ABCD whose vertices are at -1 4 and 3 7 and 5 2 and -4 -17 respectively on the Cartesian plane?
Its diagonals intersect each other at right angles when plotted on the Cartesian plane Its diagonal lengths are 2 times square root of 10 and 8 times square root of 10 Its area is 0.5 times product of its diagonals equals 80 square units
What type of triangle is triangle AOB if the parallelogram ABCD is a rhombus?
it is a right triangle because a rhombus' diagonals are perpendicular
