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Q: What is a system of equations that equals -3 and 7?

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are you talking about a system of equations where x+3y=-7 -x+2y=-8 if so, then the answer is {2,-3}

Inconsistent linear equations in two variables.

The easiest way to solve this system of equations is to solve for a variable in one of the equations. In the second equation, y = 3x. This can be substituted into the first equation: y = -4x - 7; 3x = = -4x - 7; 7x = -7; x = -1. Since we have determined that x equals -1, we can then substitute -1 into either equation to find our corresponding y-value. Thus: y = 3x; y = 3(-1) y = -3. Thus, the solution to this system of equations is (-1, -3).

Add the two equations and get 4x = 12 so x = 3 and y = -1

Equations: 3x-5y = 16 and xy = 7 Solutions: (7, 1) and (-5/3, -21/5)

A system of equations? Try elimination. - 2(-3X + Y = 7) 5X + 2Y = 3 6X - 2Y = - 14 5X + 2Y = 3 --------------------------add 11X = - 11 X = - 1 ------------Put back in equation to solve for Y - 3(-1) + Y = 7 3 + Y = 7 Y = 4 -------------check both equations - 3(-1) + 4 = 7 3 + 4 = 7 top checks 5(-1) + 2(4) = 3 - 5 + 8 = 3 both equations check and the system is consistent

x = -3 y = -2

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Add the two equations: 3x = 15 Divide by 3: x = 5, making y = -3. Job done.

X - Y = 10 X + Y = 4 -------------------+ ( add them ) 2X = 14 X = 7 ----------find Y in one of the equations; top looks good 7 - Y = 10 - Y = 3 Y = - 3 ---------------check both equations for consistency 7 - (- 3) = 10 7 + 3 = 10 10 = 10 ------------checks in top 7 + (- 3) = 4 7 - 3 = 4 4 = 4 ------------checks and is consistent (7, - 3) ( the answer )

They are simultaneous equations and their solutions are x = 41 and y = -58

15+7=22

1 and 3/4

Rearrange the second equation to read 2x - y = -3Add the two equations: 3x = 6:Divide by 3: x = 2 so y = 7

If 3x -5y = 16 and xy = 7 then by combining both equations into a single quadratic equation and solving it then the points of intersection are at (-5/3, -21/5) and (7, 1)

Math equations have an equals sign such as: 7+5=12 or 9x6=47+7 Math expressions do not have a equals sign such as: 43-27 or 8x40

x2 + 3y = 7 3x + y2 = 3 3y = x2 + 7 y2 = -3x + 3 y = x2/3 + 7/3 y = ± √(-3x + 3) If you draw the graphs of y = x2/3 + 7/3 and y = ± √(-3x + 3) in a graphing calculator, you will see that they don't intersect, so that the system of the given equations has not a solution.

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Expression. Equations have equals signs.

If: -x-3y = -4 and 3x+5y = 16 Then: x = 7 and y = -1

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Equations that have letters are just called equations, but there are types 1, 2, 3, 4 and ratio type equations. Ratio type equations are the ones where it is a fraction on both sides of the equals sign. Equation (Type 2): x+1-5=12 Ratio Type Equation: 21/7=42-x/3

Both equations are equal and so: 3x+1 = 2x+3 3x-2x = 3-1 x = 2 and by substituting y = 7

We have the given equations 4x+y=7 2x-3y=-7 First we want to make it so that we have a variable with the same coefficient in both equations. We will use the x. so we have 4x+y=7 and 2x-3y=-7. We can multiply or divide both sides of either equation by the same number without changing the equation, so we will take 2x-3y=-7 times 2 2(2x-3y)=2(-7) distribute 4x-6y=14 now we can use elimination. 4x+y=7 -(4x-6y=-14) 7y=21 divide by 7 7y/7= 21/7 y=3 Now we plug 3 into one of the original equations. 4x+3=7 subtract 4x+3-3=7 -3 4x=4 divide 4x/4= 4/4 x=1 so, the solution to our system of equations is (1,3)

7.