Systems of equations don't equal numbers.
are you talking about a system of equations where x+3y=-7 -x+2y=-8 if so, then the answer is {2,-3}
The easiest way to solve this system of equations is to solve for a variable in one of the equations. In the second equation, y = 3x. This can be substituted into the first equation: y = -4x - 7; 3x = = -4x - 7; 7x = -7; x = -1. Since we have determined that x equals -1, we can then substitute -1 into either equation to find our corresponding y-value. Thus: y = 3x; y = 3(-1) y = -3. Thus, the solution to this system of equations is (-1, -3).
Inconsistent linear equations in two variables.
Add the two equations and get 4x = 12 so x = 3 and y = -1
Equations: 3x-5y = 16 and xy = 7 Solutions: (7, 1) and (-5/3, -21/5)
Add the two equations: 3x = 15 Divide by 3: x = 5, making y = -3. Job done.
x = -3 y = -2
7
X - Y = 10 X + Y = 4 -------------------+ ( add them ) 2X = 14 X = 7 ----------find Y in one of the equations; top looks good 7 - Y = 10 - Y = 3 Y = - 3 ---------------check both equations for consistency 7 - (- 3) = 10 7 + 3 = 10 10 = 10 ------------checks in top 7 + (- 3) = 4 7 - 3 = 4 4 = 4 ------------checks and is consistent (7, - 3) ( the answer )
They are simultaneous equations and their solutions are x = 41 and y = -58
Rearrange the second equation to read 2x - y = -3Add the two equations: 3x = 6:Divide by 3: x = 2 so y = 7
If 3x -5y = 16 and xy = 7 then by combining both equations into a single quadratic equation and solving it then the points of intersection are at (-5/3, -21/5) and (7, 1)