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A = lw = 13 x 5 = 65
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What is the area of a rectangle with a perimeter of 36 inches and a length of 5 inches?
With a perimeter of 36, and a known width of 5, that means the length is 13. This makes the area 65.Perimeter = (2 x Length) + (2 x Width)Width = [Perimeter - (2 x Length)]/2= [36 -(2 x 13)]/2= (36 - 26)/2= 10/2= 5 inchesArea = Length x Width= 13 x 5= 65 square inches
The length of a rectangle is 3 inches more than twice its width its area is 65 inches sq find the length and width of the rectangle?
Length= 3 + 2W Area [65]= L x W You can use guess and check put plugging in 1,2,3... etc to do this one. I got Length= 13 and Width= 5 5 x 13 = 65
If Length of rectangle is 5 cm the width is?
If you have the area then you can find the width by dividing the area by the length...having the length by itself is broad
The area of a rug is 66 square feet the length is 5 feet longer than the width what is the width of the rug?
Area= length * width length= width + 5 so.... Area= width * (width + 5) Area= width^2 + 5width (going to use w for width.) 66= w^2 + 5w w^2 + 5w - 66= 0 Now factor! (w - 6)(w + 11) Solve for w, and since area can't be negative, you get.. w=6 length= 6+5= 11
How do you draw square with area of ten?
width 1, length 10 width 2, length 5
What is the area of a rectangle with a perimeter of 36 inches and a length of 5 inches?
With a perimeter of 36, and a known width of 5, that means the length is 13. This makes the area 65.Perimeter = (2 x Length) + (2 x Width)Width = [Perimeter - (2 x Length)]/2= [36 -(2 x 13)]/2= (36 - 26)/2= 10/2= 5 inchesArea = Length x Width= 13 x 5= 65 square inches
The length of a rectangle is 3 inches more than twice its width its area is 65 inches sq find the length and width of the rectangle?
Length= 3 + 2W Area [65]= L x W You can use guess and check put plugging in 1,2,3... etc to do this one. I got Length= 13 and Width= 5 5 x 13 = 65
How do you find the area of a rectangle with the diagonal of 13 and a width of 5?
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
Area of rectangle-?
length times width
If Length of rectangle is 5 cm the width is?
If you have the area then you can find the width by dividing the area by the length...having the length by itself is broad
If a rectangle has a diagonal of 13 and length of 12 what is its width?
Width is 5.
The area of a rug is 66 square feet the length is 5 feet longer than the width what is the width of the rug?
Area= length * width length= width + 5 so.... Area= width * (width + 5) Area= width^2 + 5width (going to use w for width.) 66= w^2 + 5w w^2 + 5w - 66= 0 Now factor! (w - 6)(w + 11) Solve for w, and since area can't be negative, you get.. w=6 length= 6+5= 11
What is a rule for the area of a square?
length x width= area ex if the length of the square was 10 and the width was 5, 10 x 5= 50units^2
The length of a rectangle is 5 more then the width Find the perimeter and the area of the rectangle?
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
What is the area of 5m length and 3m width?
Area = Length * Width = 5 m * 3 m = 15 square metres
What is the area of a photo that measures 3 by 5 inches?
The area of a rectangle is length times width. If length and width are in inches, the area will be square inches.
How do you draw square with area of ten?
width 1, length 10 width 2, length 5
