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What is the area of a rectangle with a perimeter of 36 inches and a length of 5 inches?
With a perimeter of 36, and a known width of 5, that means the length is 13. This makes the area 65.Perimeter = (2 x Length) + (2 x Width)Width = [Perimeter - (2 x Length)]/2= [36 -(2 x 13)]/2= (36 - 26)/2= 10/2= 5 inchesArea = Length x Width= 13 x 5= 65 square inches
The length of a rectangle is 3 inches more than twice its width its area is 65 inches sq find the length and width of the rectangle?
Length= 3 + 2W Area [65]= L x W You can use guess and check put plugging in 1,2,3... etc to do this one. I got Length= 13 and Width= 5 5 x 13 = 65
If Length of rectangle is 5 cm the width is?
If you have the area then you can find the width by dividing the area by the length...having the length by itself is broad
The area of a rug is 66 square feet the length is 5 feet longer than the width what is the width of the rug?
Area= length * width length= width + 5 so.... Area= width * (width + 5) Area= width^2 + 5width (going to use w for width.) 66= w^2 + 5w w^2 + 5w - 66= 0 Now factor! (w - 6)(w + 11) Solve for w, and since area can't be negative, you get.. w=6 length= 6+5= 11
How do you draw square with area of ten?
width 1, length 10 width 2, length 5
