0
A = lw = 13 x 5 = 65
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
What is the area of a rectangle with a perimeter of 36 inches and a length of 5 inches?
With a perimeter of 36, and a known width of 5, that means the length is 13. This makes the area 65.Perimeter = (2 x Length) + (2 x Width)Width = [Perimeter - (2 x Length)]/2= [36 -(2 x 13)]/2= (36 - 26)/2= 10/2= 5 inchesArea = Length x Width= 13 x 5= 65 square inches
The length of a rectangle is 3 inches more than twice its width its area is 65 inches sq find the length and width of the rectangle?
Length= 3 + 2W Area [65]= L x W You can use guess and check put plugging in 1,2,3... etc to do this one. I got Length= 13 and Width= 5 5 x 13 = 65
If Length of rectangle is 5 cm the width is?
If you have the area then you can find the width by dividing the area by the length...having the length by itself is broad
The area of a rug is 66 square feet the length is 5 feet longer than the width what is the width of the rug?
Area= length * width length= width + 5 so.... Area= width * (width + 5) Area= width^2 + 5width (going to use w for width.) 66= w^2 + 5w w^2 + 5w - 66= 0 Now factor! (w - 6)(w + 11) Solve for w, and since area can't be negative, you get.. w=6 length= 6+5= 11
What is the area of a photo that measures 3 by 5 inches?
The area of a rectangle is length times width. If length and width are in inches, the area will be square inches.
What is the area of a rectangle with a perimeter of 36 inches and a length of 5 inches?
With a perimeter of 36, and a known width of 5, that means the length is 13. This makes the area 65.Perimeter = (2 x Length) + (2 x Width)Width = [Perimeter - (2 x Length)]/2= [36 -(2 x 13)]/2= (36 - 26)/2= 10/2= 5 inchesArea = Length x Width= 13 x 5= 65 square inches
The length of a rectangle is 3 inches more than twice its width its area is 65 inches sq find the length and width of the rectangle?
Length= 3 + 2W Area [65]= L x W You can use guess and check put plugging in 1,2,3... etc to do this one. I got Length= 13 and Width= 5 5 x 13 = 65
How do you find the area of a rectangle with the diagonal of 13 and a width of 5?
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
Area of rectangle-?
length times width
If a rectangle has a diagonal of 13 and length of 12 what is its width?
Width is 5.
If Length of rectangle is 5 cm the width is?
If you have the area then you can find the width by dividing the area by the length...having the length by itself is broad
The area of a rug is 66 square feet the length is 5 feet longer than the width what is the width of the rug?
Area= length * width length= width + 5 so.... Area= width * (width + 5) Area= width^2 + 5width (going to use w for width.) 66= w^2 + 5w w^2 + 5w - 66= 0 Now factor! (w - 6)(w + 11) Solve for w, and since area can't be negative, you get.. w=6 length= 6+5= 11
What is a rule for the area of a square?
length x width= area ex if the length of the square was 10 and the width was 5, 10 x 5= 50units^2
The length of a rectangle is 5 more then the width Find the perimeter and the area of the rectangle?
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
What is the area of 5m length and 3m width?
Area = Length * Width = 5 m * 3 m = 15 square metres
How do you draw square with area of ten?
width 1, length 10 width 2, length 5
What is the area of a photo that measures 3 by 5 inches?
The area of a rectangle is length times width. If length and width are in inches, the area will be square inches.
