-2
The derivative of ( e^{2x} ) can be found using the chain rule. The derivative is ( 2e^{2x} ), where the factor of 2 comes from differentiating the exponent ( 2x ). Thus, ( \frac{d}{dx} e^{2x} = 2e^{2x} ).
d/dx sec(2x) = 2sec(2x)tan(2x)
-2
4
2x
You are supposed to use the chain rule for this. First step: derivative of root of sin2x is (1 / (2 root of sin 2x)) times the derivative of sin 2x. Second step: derivative of sin 2x is cos 2x times the derivative of 2x. Third step: derivative of 2x is 2. Finally, you need to multiply all the parts together.
-2
I'm not sure what you're asking. The derivative of sin(2x^2) is 4xcos(2x^x)dx.The derivative of (sin(2x^2)^2) is 8xsin(2x^2)cos(2x^2)dx.
It is -2*exp(-2x)
2x
3
d/dx sec(2x) = 2sec(2x)tan(2x)
2x is the first derivative of x2.
2x is the first derivative of x2.
-2
d/dx 2x^2 = 4x
All it means to take the second derivative is to take the derivative of a function twice. For example, say you start with the function y=x2+2x The first derivative would be 2x+2 But when you take the derivative the first derivative you get the second derivative which would be 2