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What is the derivative of 2x?
-2
What is x squared times 2x squared?
2x to the fourth
What is the derivative of Exp (-2x)?
It is -2*exp(-2x)
How do you find second derivative of a function?
All it means to take the second derivative is to take the derivative of a function twice. For example, say you start with the function y=x2+2x The first derivative would be 2x+2 But when you take the derivative the first derivative you get the second derivative which would be 2
-2x squared -4x squared?
2
What is the anti derivative of 2x?
x squared
What is the derivative of 1 over 2x?
It is -1 over x-squared.
What is the derivative of 2x-squared plus 4x plus 8?
The derivative of 2x2 + 4x + 8 is 4x+4.
What is the derivative of e to the power ln x squared?
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
What is the derivative of x squared?
f'(x)xy=yx(y-1) f'(x)2=2x1=2x
What is the derivative of root sin2x?
You are supposed to use the chain rule for this. First step: derivative of root of sin2x is (1 / (2 root of sin 2x)) times the derivative of sin 2x. Second step: derivative of sin 2x is cos 2x times the derivative of 2x. Third step: derivative of 2x is 2. Finally, you need to multiply all the parts together.
What is 2x squared?
2x squared can best be describe as some variable being double and then squared.
What is the derivative of 2x?
-2
What is the derivative of sin2x2?
I'm not sure what you're asking. The derivative of sin(2x^2) is 4xcos(2x^x)dx.The derivative of (sin(2x^2)^2) is 8xsin(2x^2)cos(2x^2)dx.
What is 2x -2 squared?
2x -2 squared = 0
What is x squared times 2x squared?
2x to the fourth
Why does an answer to an integration problem involve a Constant of Integration?
The indefinite integral is the anti-derivative - so the question is, "What function has this given function as a derivative". And if you add a constant to a function, the derivative of the function doesn't change. Thus, for example, if the derivative is y' = 2x, the original function might be y = x squared. However, any function of the form y = x squared + c (for any constant c) also has the SAME derivative (2x in this case). Therefore, to completely specify all possible solutions, this constant should be added.
