how does the rate law show how concentration changes after the rate of reaction
Rate of flow varies as R^4 where R is the radius or Rate of flow = (k) x (R^4)
22600
A = P*(1+R/100)T Where A = amount P = Principal R = Interest Rate (in percentage), and T = Time Since R and T are known, you can calculate (1+R/100)T = k, say. Then A = P*k so that P = A/k
meters grams like K H D M D C M m is meters the unit rate for measuring the unit rate is like the middle value
answer is 5.4 (mol/L)/s
0.54 (mol/L)/s
5.4 (apex)
4.5 (mol/L)/s
They are experimentally determined exponents.
A rate constant
First order rate constant k is described in V=k[EA] while second order rate constant is given as V=k[E][A]. For reactions that do not have true order, k is the apparent rate constant.
A relative rate constant the rate at which a reaction will take place. Ex. V = k [A][B] the constant ,k, is a constant value for the rate of the reaction in said equation.
Rate = k[A]m[B]n
how does the rate law show how concentration changes after the rate of reaction
The rate would be four times larger
Dynamite exploding