a log is the 'undo-er' of powers, kind of like division is the 'undo-er' of multiplication. EX: 102 = 100, then log10(100) = 2 103 = 1000, then log10(1000) = 3, in this example, we are using log base 10, this is a default base and sometimes isn't even wirten. e is probably the most common base but log base e is more simply called the natural log, or ln. so in general: logx(m) = N means that xN = m so log5(125) = 3 because 53 = 125.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals".
Definition to use for the log (logarithm):the logarithm of a number (n) to a given base (b) is the exponent (e) to which the base must be raised in order to produce that number.(Raising to the power is the inverse of taking the logarithm.)logb(n) = e or be = nFor example, the logarithm of 1000 to base 10 is 3 ( log10(1000) = 3),because 10 to the power of 3 is 1000: 103 = 1000.-log10[H+] is (by definition) used to calculate the pH of a dilute solution in which [H+] = concentration of H+ (or H3O+) in mol/L.pH = -log10[H+] or [H+] = 10-pH
There is no simple answer. 10 to the power 1.995635 (approx) = 99 The number 1.995635 is log10(99)
No. Log x may be written more explicitly as log10(x). That is, the logarithm of x to the base 10. Assuming that In x is a misprint for ln x, this is loge(x) ie the logarithm of e to the base e. log10(x) = loge(x)/loge(10)
logx(3) = log10(7) (assumed the common logarithm (base 10) for "log7") x^(logx(3)) = x^(log10(7)) 3 = x^(log10(7)) log10(3) = log10(x^(log10(7))) log10(3) = log10(7)log10(x) (log10(3)/log10(7)) = log10(x) 10^(log10(3)/log10(7)) = x
pH = -log10[H+] = -log10(0.001 mol/L )= -log10(10-3)= 3
A decibel (dB) has meaning only when compared a quantity (P1, V1, or I1) with a reference (P0, V0, or I0). Since it is a ratio of two like quantities, it is dimensionless. For a power ratio, power gain = 10 * log10(P1/Po) in [dB]. For a voltage ratio, voltage gain = 20 * log10(V1/Vo) in [dB]. For example, when P1 = 100 * P0, the power gain = 10 * log10(100) [dB] = 20 dB.
Let us assume you have a Hydrochloric acid solution of 0.1 M. The pH is - log10[H+]. So log10[0.1] = -1 easy way to remember this is 103 =1000 log 101000 = 3 102 =100 log 10100 = 2 101 =10 log 1010 = 1 100 =1 log 101 = 0 10-1 =0.1 log 100.1 = -1 10-2 =0.01 log 100.01 = -2 So log10[0.1] = -1 and thus pH is - log10[H] = (minus minus 1) = 1
ln(x) = log10(X)/log10(e)
That goes beyond the capabilities of most scientific calculators, but you can calculate it with logarithms:x = 7^2011 log10(x) = log10(7^2011) log10(x) = 2011 log10(7) x = 10^(2011 log10 7) x = 10^1.699,49 x = 10^0.49 times 10^1699 x = 3.09 times 10^1699
4
log10(0.083) = -1.0809 (rounded)
The little 'p' means -log10 (that's the negative log to base 10). Thus pH means -log10(Hydrogen ion concentration) → pH of the solution = -log10(7.0 x 10-2) ≈ 1.15
•Loge[H+] > Log10[H+]/Log10e
PdBm = 10*log10(1000*W)
log10 0 is actually undefined. Think about it like this: If loba b = y then we know that ay = b This means that log10 0 = y translates to 10y = 0 But as you know, 10y is always greater than zero. Therefore 10y = 0 is undefined. Therefore log10 0 = y is undefined.