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Q: What is one of the four numbers where n factorial has n digits?
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Factorial n, written n!, is equal to the product of all integer numbers between and including 1 and n. In other words, n! = 1*2*3*4...*n You could find all four numbers by brute force, evaluating the values of n! and counting the number of digits in each. This is tedious, but the first solution is easy: 1! = 1, which has one digit, so the criteria you established are met when n = 1. From the person who posted this: First of all, thanks for the quick answer. Second of all, I know that n can equal 1, but i need the other 3. Especially those that are under 31. 24 works.


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