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Q: What is q in thermodynamic equation is?
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Give the statement of second low of thermodynamic?

What is the second low of thermodynamic? In:http://wiki.answers.com/Q/FAQ/2437-487, http://wiki.answers.com/Q/FAQ/2455-1717, http://wiki.answers.com/Q/FAQ/2873-124 [Edit categories]


In this equation what does Q repressent?

Depends on the equation. If it is similar to: Q = m*Cp*dT then Q = energy if it is similar to A= Ao * exp (-Q/RT) then Q is the activation energy


In the equation Q 12 89 what is the value of Q?

Why don't you express the equation verbally? Q 12 89 doesn't have much meaning.


In the equation Q subtract 12 equals 89 what is the value of Q?

Q - 12 = 89 Add 12 to both sides of the equation. Q - 12 + 12 = 89 + 12 Q = 101


Is the gibbs free energy equation used to measure thermodynamic functions from equilibrium measurements at different temperatures?

yes it does.


How do you translate 4 multiplied by q to an algebraic equation?

4 x q=


What does q mean in the equation q equals ml?

amount of heat energy


In the equation Q 12 equals 89 what is the value of Q?

Do you mean 12Q = 89? Q = 89/12 Q = 7.4166666666666666666666


What would q equal if the equation is q plus 14 equals 99?

85


What is the point slope equation if the slope is 2?

If (p, q) is any point on the line, then the point slope equation is: (y - q)/(x - p) = 2 or (y - q) = 2*(x - p)


What is Equation of state?

In cosmology, the equation of state of a perfect fluid is characterized by a dimensionless number w, equal to the ratio of its pressure p to its energy density ρ: . It is closely related to the thermodynamic equation of state and ideal gas law.


–q = –5 what is the answer to that?

The answer to the equation -q = -5 is indeed q = 5. When we have a negative sign on both sides of the equation, they cancel each other out, resulting in q = 5. As for the expression 8-q+4 = -q+4⋅46, it seems to be an unrelated equation. Without a clear question or instructions, it's not possible to determine what you are asking for. If you provide more context or specific instructions, I'll be happy to assist you further.