p q and p q cannot be a useful part of a system of simultaneous equations since they are the same!
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If the solutions are p and q, then the quadratic is (x-p)(x-q) = 0 or x2 - (p+q)x + pq = 0 Hope this is what the question meant!
Two ratios, p/q and r/s (q and s non-zero) are equal if p/q - r/s = 0.
If the two axes intersect at the point (p, q), then the equation is: (x -p)2/25 + (y - q)2/9 = 1
p and q