Q - 12 = 89 Add 12 to both sides of the equation. Q - 12 + 12 = 89 + 12 Q = 101
It is an equation and the value of x is 2
5x+y = 2 5x-3y = 14 Subtract the bottom equation from the top equation: 4y = -12 y = -3 Substitute the value of y into the original equations to find the value of x: So: x = 1 and y = -3
Put x = 1 in the equation. So 6*1 - 2y = 12 that is, 6 - 2y = 12 Subtract 6 from both sides: -2y = 6 Divide both sides by -2: y = 6/-2 = -6/2 = -3
x = 12
So, 3 + 12 = n + 3. Subtract 3 from both sides of the equation and get 12 = n or n = 12 if you prefer.
It is an equation and the value of x is 2
You can first subtract 2 from 12 to get 10. Then when you bring 10 across the = sign, it becomes -10, so 42-10 is 32.
5x+y = 2 5x-3y = 14 Subtract the bottom equation from the top equation: 4y = -12 y = -3 Substitute the value of y into the original equations to find the value of x: So: x = 1 and y = -3
It is an equation and the value of x is 20
Put x = 1 in the equation. So 6*1 - 2y = 12 that is, 6 - 2y = 12 Subtract 6 from both sides: -2y = 6 Divide both sides by -2: y = 6/-2 = -6/2 = -3
Multiply first equation by 2: 4x - 2y = 20 Subtract second equation: x = 12, so y = 14.
x = 12
It is an equation and the value of x is 12
To solve for b in the equation b + 15 = 27, you need to isolate b on one side of the equation. To do this, you can subtract 15 from both sides of the equation. This gives you b = 27 - 15, which simplifies to b = 12. Therefore, b equals 12 in the given equation.
So, 3 + 12 = n + 3. Subtract 3 from both sides of the equation and get 12 = n or n = 12 if you prefer.
7.5
This question is really asking you to find the value of x. Once you have found the x value you can prove or disprove the equation. To solve for x, isolate it in the equation. 3x + 12 = 5x +4 (Subtract 4 from both sides) 3x + 8 = 5x (Subtract 3x from both sides) 8 = 2x (divide both sides by 2) 4 = x So, if x = 4 does that prove your equation is correct? 3(4) + 12 = 24 5(4) + 4 = 24