tan 45 = 1
tan 45° = 1
It isn't, but here is a corrected equation that is: tan1 x tan 20 x tan 45 x tan 70 x tan 89 = 1 It will then work because tan(45 + x) = 1/tan(45 - x). Hence tan1 cancels when multiplied with tan89, and tan20 cancels with tan70. tan 45 equals 1, and so the whole expression cancels to 1. I think this effect was what the equation was intended to demonstrate.
45 degrees?
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (80 ft × tan 45° × tan 34°)/(tan 45° - tan 34°) ≈ 165.78 ft
45*
cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)
tan(135) = -tan(180-135) = -tan(45) = -1
tan 45° = 1
They are both trig values, but not equal. Tan 45 is 1 and sin 45 is 0.7071
It isn't, but here is a corrected equation that is: tan1 x tan 20 x tan 45 x tan 70 x tan 89 = 1 It will then work because tan(45 + x) = 1/tan(45 - x). Hence tan1 cancels when multiplied with tan89, and tan20 cancels with tan70. tan 45 equals 1, and so the whole expression cancels to 1. I think this effect was what the equation was intended to demonstrate.
exactly 1
45 degrees?
1.00
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (80 ft × tan 45° × tan 34°)/(tan 45° - tan 34°) ≈ 165.78 ft
45*
1.00
Is the '1' one degree , or one radian or, Tan(angle) = 1. You need to clarify. However, Tan(1 degree) = 0.017455... Tan( 1 radian) = 1.55740.... Tan(angle) = 1 Angle = Tan^(-1) 1 = 45 degrees. = pi/4 radians.