tan(135) = -tan(180-135) = -tan(45) = -1
If tan 3a is equal to sin cos 45 plus sin 30, then the value of a = 0.4.
cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)
To find the value of z, set up the equation: 9z = 135 (then divide both sides of the equation by 9) z = 15
I really don't know
tan (pi) / 1 is zero. tan (pi / 1) is zero.
tan(135 degrees) = negative 1.
The value of tan A is not clear from the question.However, sin A = sqrt[tan^2 A /(tan^2 A + 1)]
Absolute value of -135 is 135.
You find the smallest positive value y such that tan(x + y) = tan(x) for all x.
To find the value of (\tan(15^\circ) \tan(195^\circ)), we can use the identity (\tan(195^\circ) = \tan(15^\circ + 180^\circ) = \tan(15^\circ)). Thus, (\tan(195^\circ) = \tan(15^\circ)). Consequently, (\tan(15^\circ) \tan(195^\circ) = \tan(15^\circ) \tan(15^\circ) = \tan^2(15^\circ)). The exact value of (\tan^2(15^\circ)) can be computed, but it is important to note that it will yield a positive value.
tan u/2 = sin u/1+cos u
If tan 3a is equal to sin cos 45 plus sin 30, then the value of a = 0.4.
It is 30 which is thirty
6.25
cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)
tan(22.5)=0.414213562
To find the exact value of (\tan 150^\circ), you can use the fact that (150^\circ) is in the second quadrant, where the tangent function is negative. The reference angle for (150^\circ) is (180^\circ - 150^\circ = 30^\circ). Therefore, (\tan 150^\circ = -\tan 30^\circ). Since (\tan 30^\circ = \frac{1}{\sqrt{3}}), it follows that (\tan 150^\circ = -\frac{1}{\sqrt{3}}), or (-\frac{\sqrt{3}}{3}) when rationalized.