Q: How do you find the value of tan 135?

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If tan 3a is equal to sin cos 45 plus sin 30, then the value of a = 0.4.

cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)

To find the value of z, set up the equation: 9z = 135 (then divide both sides of the equation by 9) z = 15

tan (pi) / 1 is zero. tan (pi / 1) is zero.

I really don't know

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tan(135 degrees) = negative 1.

The value of tan A is not clear from the question.However, sin A = sqrt[tan^2 A /(tan^2 A + 1)]

Absolute value of -135 is 135.

You find the smallest positive value y such that tan(x + y) = tan(x) for all x.

tan u/2 = sin u/1+cos u

If tan 3a is equal to sin cos 45 plus sin 30, then the value of a = 0.4.

It is 30 which is thirty

6.25

cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)

tan(22.5)=0.414213562

Rfh

tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2