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tan 45 = 1

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15y ago

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What is the tangent of 45 degrees?

tan 45° = 1


How Tan1Tan20Tan45tan60Tan79 is equal to 1?

It isn't, but here is a corrected equation that is: tan1 x tan 20 x tan 45 x tan 70 x tan 89 = 1 It will then work because tan(45 + x) = 1/tan(45 - x). Hence tan1 cancels when multiplied with tan89, and tan20 cancels with tan70. tan 45 equals 1, and so the whole expression cancels to 1. I think this effect was what the equation was intended to demonstrate.


What is the angle of a tan rhombus?

45 degrees?


What is the approximate height of a building when the angle of elevation at the top of a building is 34 degrees and at a point 80 feet closer the angle of elevation is 45 degrees?

It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (80 ft × tan 45° × tan 34°)/(tan 45° - tan 34°) ≈ 165.78 ft


What is the value of tan 15 degree in fraction?

The value of ( \tan 15^\circ ) can be calculated using the tangent subtraction formula: [ \tan(15^\circ) = \tan(45^\circ - 30^\circ) = \frac{\tan 45^\circ - \tan 30^\circ}{1 + \tan 45^\circ \tan 30^\circ} ] Substituting the known values ( \tan 45^\circ = 1 ) and ( \tan 30^\circ = \frac{1}{\sqrt{3}} ), we find: [ \tan(15^\circ) = \frac{1 - \frac{1}{\sqrt{3}}}{1 + 1 \cdot \frac{1}{\sqrt{3}}} = \frac{\sqrt{3} - 1}{\sqrt{3} + 1} ] Thus, ( \tan 15^\circ = 2 - \sqrt{3} ) in its simplest fractional form.

Related Questions

What is the exact trigonometric function value of cot 15 degrees?

cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)


How do you find the value of tan 135?

tan(135) = -tan(180-135) = -tan(45) = -1


What is the tangent of 45 degrees?

tan 45° = 1


Does tan 45 degrees and sin 45 degrees equal trig values?

They are both trig values, but not equal. Tan 45 is 1 and sin 45 is 0.7071


How Tan1Tan20Tan45tan60Tan79 is equal to 1?

It isn't, but here is a corrected equation that is: tan1 x tan 20 x tan 45 x tan 70 x tan 89 = 1 It will then work because tan(45 + x) = 1/tan(45 - x). Hence tan1 cancels when multiplied with tan89, and tan20 cancels with tan70. tan 45 equals 1, and so the whole expression cancels to 1. I think this effect was what the equation was intended to demonstrate.


What is the angle of a tan rhombus?

45 degrees?


What is tan 45 degrees?

exactly 1


The tan of a 45 degree angle?

1.00


What is the approximate height of a building when the angle of elevation at the top of a building is 34 degrees and at a point 80 feet closer the angle of elevation is 45 degrees?

It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (80 ft × tan 45° × tan 34°)/(tan 45° - tan 34°) ≈ 165.78 ft


What is the value of tan 15 degree in fraction?

The value of ( \tan 15^\circ ) can be calculated using the tangent subtraction formula: [ \tan(15^\circ) = \tan(45^\circ - 30^\circ) = \frac{\tan 45^\circ - \tan 30^\circ}{1 + \tan 45^\circ \tan 30^\circ} ] Substituting the known values ( \tan 45^\circ = 1 ) and ( \tan 30^\circ = \frac{1}{\sqrt{3}} ), we find: [ \tan(15^\circ) = \frac{1 - \frac{1}{\sqrt{3}}}{1 + 1 \cdot \frac{1}{\sqrt{3}}} = \frac{\sqrt{3} - 1}{\sqrt{3} + 1} ] Thus, ( \tan 15^\circ = 2 - \sqrt{3} ) in its simplest fractional form.


The tan of a 45 degree angle equals?

1.00


Fill in the blank Tan equals 1?

45*