It is y1-y2=m(x1-x2). m is the slope of the line. The point should be where the 2nd y2 and x2 are. Ex: slope = 5 (3,-4) The answer to this would be: y+4=5(x-3)
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If you mean points of (7, 2) and (3, 5) then the slope is -3/4
The equation to figure out a slope is y1 - y2 / x1 - x2. In (1,9) and (-3,16), 9 is y1 and 16 is y2. 1 is x1 and -3 is x2. Now you have -7/4, which is your slope!
The slope of that would be 0.75 - if you follow the the equation; y2 - y1 x2 - x1
Slop between (x1, y1) and (x2, y2) is given by: slope = y_difference / x_difference = (y2 - y1) / (x2 - x1) For (-1, -1) to (3, 15): slope= (15 - -1) / (3 - -1) = 16 / 4 =4
the slope of a line passing via (x1,y1) and (x2,y2) is tan(theta) = m = y2-y1/x2-x1 therefore m = 12-9/4-3 = 3
The slope is hi
The slope is the change in y divided by the change in x ("rise over run"). For the points (x1, y1) and (x2, y2), the slope calculation is: ( y1 - y2 ) ( x1 - x2 ) For the points (3, -9) and (7, 6), the slope calculation is: ( -9 - 6 ) = ( -15 ) = 3.75 ( 3 - 7 ) ( -4 )
The slope = (y2 - y1)/(x2 - x1) = (7 - 3)/(4 - 1) = 4/3
slope (m) = (y2-y1)/(x2-x1) m=(1-4)/(3-2) m=-3
we have the points (3,4) and (8,-6) let x1=3 y1=4 x2=8 y2=-6 slope=(y2-y1)/(x2-x1) =(-6-4)/(8-3) =-10/5 =-2