If you mean points of (7, 2) and (3, 5) then the slope is -3/4
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
Points: (20, 18) and (35, 6) Slope: -4/5 Equation: y = -4/5x+34
It represents: y = x-35 or as x-y-35 = 0
It represents: y = x-35 or as x-y-35 = 0
To find the equation in point-slope form for the line that passes through the points (3, 5) and (2, 3), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points gives us ( m = \frac{3 - 5}{2 - 3} = \frac{-2}{-1} = 2 ). Using point-slope form ( y - y_1 = m(x - x_1) ) with point (3, 5), the equation becomes ( y - 5 = 2(x - 3) ).
If you mean points of (-2, -1) and (3, 5) then the slope is 6/5
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
Points: (20, 18) and (35, 6) Slope: -4/5 Equation: y = -4/5x+34
If you mean points of (-2, -1) and (3, 5) then the slope is 6/5
Points: (-3, 5) and (4, 9) Slope: 4/7
It represents: y = x-35 or as x-y-35 = 0
It represents: y = x-35 or as x-y-35 = 0
Slope: -35 passing through (-5, -1) Equation: y = -35x-176
To find the equation in point-slope form for the line that passes through the points (3, 5) and (2, 3), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points gives us ( m = \frac{3 - 5}{2 - 3} = \frac{-2}{-1} = 2 ). Using point-slope form ( y - y_1 = m(x - x_1) ) with point (3, 5), the equation becomes ( y - 5 = 2(x - 3) ).
To find the equation of a line in standard form (Ax + By = C) that passes through the point (-5, 1) with a slope of 7, we can use the point-slope form first: (y - 1 = 7(x + 5)). Simplifying this gives (y - 1 = 7x + 35) or (y = 7x + 36). Rearranging to standard form results in (-7x + y = 36) or (7x - y = -36). Thus, the standard form of the equation is (7x - y = -36).
It works out as 29
Points: (-3, 5) and (4, 7) Slope: 2/7