Slop between (x1, y1) and (x2, y2) is given by:
slope = y_difference / x_difference
= (y2 - y1) / (x2 - x1)
For (-1, -1) to (3, 15):
slope= (15 - -1) / (3 - -1)
= 16 / 4
=4
slope is =( 9-15 )/ (5-3) = -6/2 = -3
If you mean points of (1, 5) and (-2, -4) then the slope works out as 3
To find the slope of the line that passes through the points (9, -81) and (6, -36), use the formula for slope ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Plugging in the values, we have ( m = \frac{-36 - (-81)}{6 - 9} = \frac{45}{-3} = -15 ). Thus, the slope of the line is -15.
To find the slope of the line passing through the points (3, 15) and (5, 9), use the formula for slope ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Here, ( (x_1, y_1) = (3, 15) ) and ( (x_2, y_2) = (5, 9) ). Plugging in the values, we get ( m = \frac{9 - 15}{5 - 3} = \frac{-6}{2} = -3 ). Therefore, the slope of the line is -3.
Points: (3, 3) and (-6, -15) Slope works out as: 2
Points: (-1, -1) and (3, 15) Slope: 4
Points: (3, 15) and (5, 9) Slope: -3
Points: (0, 5) and (10, -15) Slope: -2
Points: (10, 8) and (15, 8) Slope: 0 It will be a straight horizontal line
Points: (15, 8) and (7, 3) Slope: 5/8
slope is =( 9-15 )/ (5-3) = -6/2 = -3
If you mean points of (1, 5) and (-2, -4) then the slope works out as 3
If you mean points of (1, 5) and (-1, -1) then the slope works out as 3
When given two points use the equation :- m = [y(1) - y(2)] / [ x(1) - x(2)] NB The numbers above are 'markers' , NOT the coordinates of the given points. For the points (1,1) & ( 3,15) Substitute om m = [ 15 -1] /[ 3 - 1 ] => m = [ 14] / [2] => m = 14/2 Cancel down by '2' m = 7 the slope!!!!!
The slope of the line that passes through the points (3,15) and (5,9), is -3; use the formula change in Y-axis/change in X-axis.
To find the slope of the line that passes through the points (9, -81) and (6, -36), use the formula for slope ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Plugging in the values, we have ( m = \frac{-36 - (-81)}{6 - 9} = \frac{45}{-3} = -15 ). Thus, the slope of the line is -15.
To find the slope of the line passing through the points (3, 15) and (5, 9), use the formula for slope ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Here, ( (x_1, y_1) = (3, 15) ) and ( (x_2, y_2) = (5, 9) ). Plugging in the values, we get ( m = \frac{9 - 15}{5 - 3} = \frac{-6}{2} = -3 ). Therefore, the slope of the line is -3.