Use the following formula:
an = a1 + (n - 1)d, where
a1 = the first term
n = the n th term (general term)
d = common difference (which is constant between terms)
Since we need to find the 14 th term, we can write:
a1 = 100
n = 14
d = -4
an = a1 + (n - 1)d
a14 = 100 + (14 - 1)(-4)
a14 = 100 + (13)(-4)
a14 = 100 - 52
a14 = 48
Thus, the 14 th term is 48.
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
16
6
-8
a + (n-1)d = last number where a is the first number d is the common difference.
The nth term is Un = a + (n-1)*d where a = U1 is the first term, and d is the common difference.
a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
It is a + 8d where a is the first term and d is the common difference.
16
You subtract any two adjacent numbers in the sequence. For example, in the sequence (1, 4, 7, 10, ...), you can subtract 4 - 1, or 7 - 4, or 10 - 7; in any case you will get 3, which is the common difference.
From any term after the first, subtract the preceding term.
6
The common difference is 6; each number after the first equals the previous number minus 6.
6
6
29