Q: What is the 7th term of a sequence when the rule is n2 plus 2?

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every next term is 4 smaller than previous so 7th term = -23

a7 = a1 + 6*D = 10 + 6*(-3) = 10 - 18 = -8

a7/a10 = a10/a13 = 1/r3 where r is the common ratio. So a7 = (a10)2/a13 = -81/72 = -9/8

Related questions

Find the 7th term of the geometric sequence whose common ratio is 1/2 and whose first turn is 5

The 7th term is 7 x (-2)6 = 7 x 64 = 448

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0, 1, 1, 2, 3, 5, 8 so the 7th term is 8

4096-20481024-512256-12864

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every next term is 4 smaller than previous so 7th term = -23

Each term is 5 times the previous term, so termr = 5(r-1) (with term1 = 1). So the 7th term is 57-1 = 56 = 15625.

9, 12,16,21,27,34,42 42 is the 7th term 9+3=12 12+4=16 16+5=21 21+6=27 27+7=34 34+8=42, the 7th term

Each number in the sequence is the previous number divided by 4. Therefore the 7th term starting from 1024 is 0.25. The first 8 terms are: 1024, 256, 64, 16, 4, 1, 0.25 and 0.0625.

The Fibonacci sequence has this form: Fn + 2 = Fn + 1 + Fn with these starting values F0 = 0 and F1 = 1. Find the 7th term via similar computation by substituting the values in! You should get... F2 = F1 + F0 F2 = 1 + 0 F2 = 1 F3 = F2 + F1 F3 = 1 + 1 F3 = 2 F4 = 3 F5 = 5 F6 = 8 F7 = 13 So the 7th term of the Fibonacci sequence is 13.

a7 = a1 + 6*D = 10 + 6*(-3) = 10 - 18 = -8