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Propably because it would be very difficult to measure the difference between the rings' diameters.
To find the surface area of a cylindrical ring or torus, you can use the formula A = 2πrh, where r is the average radius of the ring and h is the height or thickness of the ring. In this case, the average radius is (16mm + 10mm)/2 = 13mm and h can be any desired value. Therefore, the surface area of the cylindrical ring or torus is 2π(13mm)(h).
Outer radius = a; inner radius = b; then area of the ring = pi (a2 - b2) = 90, where pi = 22/7. In view of a = 9, we have b2 = 81 - [90 x 7 / 22], the positive square root of which gives b.
In my openion bubbles in the soap film is the real examples of it
Treat the ring as a circle. Area equals pi (3.14) times the radius squared. Whether you take the inner of the ring or the outer of the ring, rather depends on how thick the ring is - inner is probably best as that should loosely match the thickness of the finger on which the ring will eventually sit.
newtons ring is formed due to the consequtive circle of different radius of bright and dark in which the centre is dark
Propably because it would be very difficult to measure the difference between the rings' diameters.
Radius of rings is directly proportional to the square root of the radius of curvature. Thin lens would have larger radius of curvature and hence the option
The expression for the radius of the nth dark ring is given as rn2 = n R l Here l is the wavelength of monochromatic source. R- the radius of curvature of the plano convex lens n is the order of the ring. Theoretically we can get value of R knowing other quantities. But practically we use the following expression R = r n+m 2 - r n 2 / m l This would reduce the error due to non symmetry of the smaller rings.
A horse ring with a radius of 10 yards
To find the surface area of a cylindrical ring or torus, you can use the formula A = 2πrh, where r is the average radius of the ring and h is the height or thickness of the ring. In this case, the average radius is (16mm + 10mm)/2 = 13mm and h can be any desired value. Therefore, the surface area of the cylindrical ring or torus is 2π(13mm)(h).
radius
Outer radius = a; inner radius = b; then area of the ring = pi (a2 - b2) = 90, where pi = 22/7. In view of a = 9, we have b2 = 81 - [90 x 7 / 22], the positive square root of which gives b.
No your skin will form to any curvature.
let the outer radius of the ring be R inner radius r n cross sectional radius be y then the volume of the ring will be (pi)y2 X (pi)(R-r)/2 i.i the cross sectional area multiplied by the length of the ring when it was a line the length is taken at the midpoint of the thickness of the ring = (R-r)/2
1 quarter of a basketball ring
don,t know