Treat the ring as a circle. Area equals pi (3.14) times the radius squared. Whether you take the inner of the ring or the outer of the ring, rather depends on how thick the ring is - inner is probably best as that should loosely match the thickness of the finger on which the ring will eventually sit.
Calculate the area of the room. Calculate the area of the window (or whatever opening) Room Area*100/Window Area
It is not possible to calculate the area given only the volume.
Average area
The 45 degrees is an angle. To calculate an area the length and width are needed.
We can calculate the area by taking out the product of the length and the breadth of the house
length x width = area
The area of Norsebury Ring is 40,468.564224 square meters.
The area of Cissbury Ring is 819,000.0 square meters.
Area Where Earthquakes and Volcanos Are CommonThat area is called the Ring of Fire.
Calculate the area of the room. Calculate the area of the window (or whatever opening) Room Area*100/Window Area
let the outer radius of the ring be R inner radius r n cross sectional radius be y then the volume of the ring will be (pi)y2 X (pi)(R-r)/2 i.i the cross sectional area multiplied by the length of the ring when it was a line the length is taken at the midpoint of the thickness of the ring = (R-r)/2
which circumference of the basketball ring are you trying to calculate? 2d or 3d -"... 3d
Area of bullseye 102 ie 100pi; Area of inner ring and bullseye together is 252 ie 625pi, so area of inner ring is 525pi. Area of second ring and its contents is 402 ie 1600pi, contents area 625pi so area of second ring 975pi. Area of third ring and contents is 552 ie 3025pi, contents area is 1600pi so area of third ring is 1425pi Area of outer ring and contents is 702 ie 4900pi, contents area is 3025pi so area of outer ring is 1875pi. I note that for the three outer rings the area increases by 450pi each time, but for the inner ring it only increases by 425pi. What the reason for this is, I know not unless I've miscalculated somewhere...
PiR2=area
If your ring has an outer radius of 8 mm and an inner one of 5 mm, you will have pi times (routside)2 minus pi times (rinside)2 or about 122.522 square millimeters of area on the top of the ring. Double that if you add in the surface area of the bottom. As to the sides (the inside and outside), we cannot calculate them without a thickness.
It is not possible to calculate the area given only the volume.
The area of Ku-ring-gai Council is 86 square kilometers.