0
Want this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
Why should radius of curvature of lens in newton's ring apparatus be large?
Propably because it would be very difficult to measure the difference between the rings' diameters.
What is the surgace area of a cylindrical ring or torus if its outside diameter is 16mm andits inside diameter is 10mm?
To find the surface area of a cylindrical ring or torus, you can use the formula A = 2πrh, where r is the average radius of the ring and h is the height or thickness of the ring. In this case, the average radius is (16mm + 10mm)/2 = 13mm and h can be any desired value. Therefore, the surface area of the cylindrical ring or torus is 2π(13mm)(h).
The area of a circular ring is 90 if the radius of the outer circle forming the ring is 9 what is the radius of the inner circle of the ring assuming the circles forming the ring have same center?
Outer radius = a; inner radius = b; then area of the ring = pi (a2 - b2) = 90, where pi = 22/7. In view of a = 9, we have b2 = 81 - [90 x 7 / 22], the positive square root of which gives b.
What are the application of newton's ring experiment in our daily life?
In my openion bubbles in the soap film is the real examples of it
How do you calculate the area of a ring?
Treat the ring as a circle. Area equals pi (3.14) times the radius squared. Whether you take the inner of the ring or the outer of the ring, rather depends on how thick the ring is - inner is probably best as that should loosely match the thickness of the finger on which the ring will eventually sit.
What is Radius of curvature in newtons rings?
Radius of curvature in Newton's rings is the radius of the curvature of the wavefront at the point where interference fringes are observed. It is calculated by measuring the diameter of the nth dark ring and using the formula R = (n * λ * D) / (2 * δ), where R is the radius of curvature, n is the order of the ring, λ is the wavelength of light, D is the distance between the lens and the glass plate, and δ is the diameter of the nth dark ring.
What is the use of the newton's rings?
newtons ring is formed due to the consequtive circle of different radius of bright and dark in which the centre is dark
Why should radius of curvature of lens in newton's ring apparatus be large?
Propably because it would be very difficult to measure the difference between the rings' diameters.
Why should a lens of large radius of curvature is used in the Newton's ring experiment?
A lens with a large radius of curvature allows for a greater region of interference fringes to be observed, making it easier to measure the diameter of the rings accurately. This increases the precision of the experiment and reduces errors in measurement. Additionally, a large radius of curvature reduces the curvature of the lens surfaces, leading to more uniform and symmetrical interference patterns.
How can newtons rings be used to find the radius of curvature?
Newton's rings can be used to find the radius of curvature of a lens by measuring the diameter of the rings as a function of the distance from the center of the lens. By fitting the experimental data to the equation for the radius of curvature derived from the theory of interference, the radius of curvature can be determined. This method relies on understanding the interference patterns produced by the air gap between the lens and a flat glass plate.
Why do you take plano convex lens with a spherical surface of a large radius of curvayure in the newtons ring experimental set up?
In Newton's ring experiment, a plano-convex lens with a large radius of curvature is used to ensure that the interference fringes produced between the lens and the flat glass plate can be easily observed and analyzed. The large radius of curvature helps in creating distinct and well-defined interference patterns, which are essential for accurate measurement and analysis of the rings.
Why should you use a convex lens of large radius of curvature in performing newtons ring experiment?
Radius of rings is directly proportional to the square root of the radius of curvature. Thin lens would have larger radius of curvature and hence the option
Why extended source is used in the newtons ring experiment?
An extended source is used in the Newton's ring experiment to ensure that the light incident on the glass plate is coherent and uniform. This helps to produce clear and sharp interference fringes, which are essential for accurate measurements of the radius of curvature of the lens and the wavelength of light.
What is the fringe width of NEWTON RING?
The fringe width of Newton rings is the distance between two consecutive bright or dark fringes observed when a plano-convex lens is placed on a flat glass plate. It is given by the formula [ w = \lambda \cdot R / (D - R) ], where ( \lambda ) is the wavelength of light, ( R ) is the radius of curvature of the lens, and ( D ) is the diameter of the bright ring.
How we find out the refractive index of a liquid using newton's rings?
The refractive index of a liquid can be determined using Newton's rings by observing the pattern of concentric bright and dark fringes produced when light reflects off the liquid-air interface. By measuring the diameter of the rings and applying the formula relating ring radius to the refractive index of the liquid and the wavelength of light, the refractive index can be calculated. The relationship is given by: n = (R^2 - r^2) / (2t*r), where n is the refractive index, R is the radius of curvature of the lens, r is the radius of a bright ring, and t is the thickness of the liquid film.
A horse ring with a radius of 10 yards?
A horse ring with a radius of 10 yards
Is the distance between two adjacent bright ring and dark ring equal for the Newton's rings?
No, the distance between two adjacent bright and dark rings in Newton's rings pattern is not equal. The spacing between the rings decreases as we move from the center outwards, due to the curvature of the lens. This pattern is a result of the varying film thickness of air between the lens and the flat glass plate.
