Want this question answered?
Be notified when an answer is posted
Propably because it would be very difficult to measure the difference between the rings' diameters.
To find the surface area of a cylindrical ring or torus, you can use the formula A = 2πrh, where r is the average radius of the ring and h is the height or thickness of the ring. In this case, the average radius is (16mm + 10mm)/2 = 13mm and h can be any desired value. Therefore, the surface area of the cylindrical ring or torus is 2π(13mm)(h).
Outer radius = a; inner radius = b; then area of the ring = pi (a2 - b2) = 90, where pi = 22/7. In view of a = 9, we have b2 = 81 - [90 x 7 / 22], the positive square root of which gives b.
Treat the ring as a circle. Area equals pi (3.14) times the radius squared. Whether you take the inner of the ring or the outer of the ring, rather depends on how thick the ring is - inner is probably best as that should loosely match the thickness of the finger on which the ring will eventually sit.
In my openion bubbles in the soap film is the real examples of it
Radius of curvature in Newton's rings is the radius of the curvature of the wavefront at the point where interference fringes are observed. It is calculated by measuring the diameter of the nth dark ring and using the formula R = (n * λ * D) / (2 * δ), where R is the radius of curvature, n is the order of the ring, λ is the wavelength of light, D is the distance between the lens and the glass plate, and δ is the diameter of the nth dark ring.
newtons ring is formed due to the consequtive circle of different radius of bright and dark in which the centre is dark
Propably because it would be very difficult to measure the difference between the rings' diameters.
Newton's rings can be used to find the radius of curvature of a lens by measuring the diameter of the rings as a function of the distance from the center of the lens. By fitting the experimental data to the equation for the radius of curvature derived from the theory of interference, the radius of curvature can be determined. This method relies on understanding the interference patterns produced by the air gap between the lens and a flat glass plate.
Radius of rings is directly proportional to the square root of the radius of curvature. Thin lens would have larger radius of curvature and hence the option
The refractive index of a liquid can be determined using Newton's rings by observing the pattern of concentric bright and dark fringes produced when light reflects off the liquid-air interface. By measuring the diameter of the rings and applying the formula relating ring radius to the refractive index of the liquid and the wavelength of light, the refractive index can be calculated. The relationship is given by: n = (R^2 - r^2) / (2t*r), where n is the refractive index, R is the radius of curvature of the lens, r is the radius of a bright ring, and t is the thickness of the liquid film.
A horse ring with a radius of 10 yards
To find the surface area of a cylindrical ring or torus, you can use the formula A = 2πrh, where r is the average radius of the ring and h is the height or thickness of the ring. In this case, the average radius is (16mm + 10mm)/2 = 13mm and h can be any desired value. Therefore, the surface area of the cylindrical ring or torus is 2π(13mm)(h).
radius
Outer radius = a; inner radius = b; then area of the ring = pi (a2 - b2) = 90, where pi = 22/7. In view of a = 9, we have b2 = 81 - [90 x 7 / 22], the positive square root of which gives b.
let the outer radius of the ring be R inner radius r n cross sectional radius be y then the volume of the ring will be (pi)y2 X (pi)(R-r)/2 i.i the cross sectional area multiplied by the length of the ring when it was a line the length is taken at the midpoint of the thickness of the ring = (R-r)/2
No your skin will form to any curvature.