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Why should radius of curvature of lens in newton's ring apparatus be large?
Propably because it would be very difficult to measure the difference between the rings' diameters.
What is the surgace area of a cylindrical ring or torus if its outside diameter is 16mm andits inside diameter is 10mm?
To find the surface area of a cylindrical ring or torus, you can use the formula A = 2πrh, where r is the average radius of the ring and h is the height or thickness of the ring. In this case, the average radius is (16mm + 10mm)/2 = 13mm and h can be any desired value. Therefore, the surface area of the cylindrical ring or torus is 2π(13mm)(h).
The area of a circular ring is 90 if the radius of the outer circle forming the ring is 9 what is the radius of the inner circle of the ring assuming the circles forming the ring have same center?
Outer radius = a; inner radius = b; then area of the ring = pi (a2 - b2) = 90, where pi = 22/7. In view of a = 9, we have b2 = 81 - [90 x 7 / 22], the positive square root of which gives b.
How do you calculate the area of a ring?
Treat the ring as a circle. Area equals pi (3.14) times the radius squared. Whether you take the inner of the ring or the outer of the ring, rather depends on how thick the ring is - inner is probably best as that should loosely match the thickness of the finger on which the ring will eventually sit.
What are the application of newton's ring experiment in our daily life?
In my openion bubbles in the soap film is the real examples of it
