It is impossible to answer the question without information on the scaled measurements.
A cylinder with a diameter of 2 feet and a length of 4 feet has a volume of 12.57 cubic feet.
In the vicinity of 70 feet. Actual length will vary according to tractor and trailer length.
113.10 ft3
I like bacon. :D
To determine the scale of the diagram of the bridge, you need both the actual length of the bridge and the length represented in the diagram. The scale can be expressed as a ratio of the diagram length to the actual length. For example, if the diagram represents the bridge as 1,000 feet, the scale would be 1:4.2 (1,000 feet in the diagram to 4,200 feet actual). If you provide the length in the diagram, I can help you calculate the specific scale.
15.2 feet
To find the scale factor of the drawing, first convert the actual length from feet to inches since the drawing's length is in inches. There are 12 inches in a foot, so 8 feet equals 96 inches. The scale factor can then be calculated by dividing the drawing length (4 inches) by the actual length (96 inches), resulting in a scale factor of 1:24. This means that 1 inch on the drawing represents 24 inches in reality.
The actual amount of yards is 100 from touchdown to touchdown, which equals out to obviously 300 feet. But including the touchdowns length it is 10 each and comes out to 120 yards in all, or 360 feet
40 feet
A length of 5,280 feet is defined as one ' mile'.
Ask your teacher about length and area...
To find the actual length of the train, we can set up a proportion based on the scale. The model train is 35 inches long, and according to the scale, 7 inches corresponds to 90 feet. Therefore, we can calculate the actual length as follows: [ \text{Actual Length} = \left( \frac{90 , \text{feet}}{7 , \text{inches}} \right) \times 35 , \text{inches} = 450 , \text{feet}. ] Thus, the actual length of the train is 450 feet.