To find the scale factor of the drawing, first convert the actual length from feet to inches since the drawing's length is in inches. There are 12 inches in a foot, so 8 feet equals 96 inches. The scale factor can then be calculated by dividing the drawing length (4 inches) by the actual length (96 inches), resulting in a scale factor of 1:24. This means that 1 inch on the drawing represents 24 inches in reality.
To determine the length of the object in the drawing, use the scale of 3 inches for every 4 feet. First, find the ratio of the actual length to the scale length: ( 24 \text{ ft} \div 4 \text{ ft} = 6 ). Then, multiply this ratio by the scale length: ( 6 \times 3 \text{ in} = 18 \text{ in} ). Therefore, the length of the object in the drawing is 18 inches.
7 inches is 7 inches. 7 inches is the actual length of 7 inches.
The scale factor.
To find the actual length of the train, we can set up a proportion based on the scale. The model train is 35 inches long, and according to the scale, 7 inches corresponds to 90 feet. Therefore, we can calculate the actual length as follows: [ \text{Actual Length} = \left( \frac{90 , \text{feet}}{7 , \text{inches}} \right) \times 35 , \text{inches} = 450 , \text{feet}. ] Thus, the actual length of the train is 450 feet.
If the dimensions of the actual playground are 50 times those of the scale drawing, then the length and width of the actual playground can be represented as 50 times the length and width of the scale drawing. The area of a rectangle is calculated by multiplying length by width. Since the area of the scale drawing is 6 square feet, the area of the actual playground will be ( (50 \times \text{length}) \times (50 \times \text{width}) = 2500 \times \text{(length} \times \text{width)} ). Therefore, the area of the actual playground is ( 2500 \times 6 = 15,000 ) square feet.
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It would be: 96/12 = 8 inches
The scale factor of a scale drawing is the ratio of any length in the drawing to the true corresponding length in the "real" object.
7 inches is 7 inches. 7 inches is the actual length of 7 inches.
The scale factor.
The scale indicates how many units of length of the actual object are represented by each unit of length in the drawing.
To find the length of the park on the map, you can use the scale factor. The scale factor is calculated by dividing the actual length by the corresponding length on the map. In this case, the actual length is 9.1 miles and the width on the map is 2.13 inches. So, the length on the map would be 9.1 / 6.5 * 2.13 = 2.97 inches.
To find the scale factor, divide the corresponding dimensions on the scale drawing by the actual dimensions. For the length, 40 ft is equal to 480 in, so the scale factor is 16 in / 480 in = 1/30. For the width, 28 ft 9 in is equal to 345 in, so the scale factor is 11.5 in / 345 in = 1/30. María used a scale factor of 1/30 in her drawing.
Step-by-step explanation: The drawing scale is 3 inches per foot. If we have the amount of inches in length, we can determine the number of feet the actual ... 2 answers · Top answer: Answer:6.67 feet longStep-by-step explanation:The drawing scale is 3 inches per foot. If we ... Missing: king | Must include: king
To find the scale of the blueprint, divide the actual length of the wall by the length on the blueprint. The actual length is 15 feet, which is equivalent to 180 inches (since 1 foot = 12 inches). The blueprint length is 5 centimeters, which is approximately 1.97 inches (since 1 centimeter ≈ 0.3937 inches). Therefore, the scale of the blueprint is 180 inches / 1.97 inches, which simplifies to approximately 91.4:1.
If the dimensions of the actual playground are 50 times those of the scale drawing, then the length and width of the actual playground can be represented as 50 times the length and width of the scale drawing. The area of a rectangle is calculated by multiplying length by width. Since the area of the scale drawing is 6 square feet, the area of the actual playground will be ( (50 \times \text{length}) \times (50 \times \text{width}) = 2500 \times \text{(length} \times \text{width)} ). Therefore, the area of the actual playground is ( 2500 \times 6 = 15,000 ) square feet.