That's not real clear. It could be 2 times positive 1 (which is 2) plus 5, which equals 7.
It could be 2x + 1 + 5 which equals 2x + 6
It could be 2x + 1 = 5, in which case x = 2
1 plus 1 x 2 plus 3 x 42 plus 10 x 5 = 1 + 2 + 126 + 50 = 179
No. In the order of operations, 5 divided by 5 comes first. Let's say x equals 2. 2 plus 5 divided by 5 plus two 2 plus 1 plus 2 3 plus 2 equals 5. The answer is 5
If: x+1+2x = 1x+5 Then: x = 2
x = -1/2 or -5 2x2 + 11x + 5 = 0 ⇒ (2x + 1)(x + 5) = 0 ⇒ (2x + 1) = 0 → x = -1/2 or (x + 5) = 0 → x = -5
x(x + 1) = x**2 + x
8-5(2+x)=2(x+1)
(x+1)(x+5)(x+2)
solving for the x variable given that x2-6x+5=0 factoring the polynomial gives (x-1)(x-5)=0 which leaves you with your two answers, x=1, 5 or you could have used the quadratic equation x = [ -(-6) plus/minus sqrt( (-6)2 - 4*1*5 ) ] / (2*1) x = [ 6 plus/minus sqrt( 36-20 ) ] / 2 x = [ 6 plus/minus 4 ] / 2 x = 3 plus/minus 2 x = 5, 1
Yes, this works, with one; 1 plus 1 over 1 = 2 No, it does not work with numbers over 2. 2 plus 1 over 2 = 1.5 3 plus 1 over 3 = 1.33333333... 4 plus 1 over 4 = 1.25 5 plus 1 over 5 = 1.2
2/x + 5
x=-1/2
x-1+5=2x-1 becomes -x = -5 so x=5