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If x is zero, then y12x is also zero. The answer is therefore 88.
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What can be learned from the first derivative?
let f be a function and f' the first derivative.If f'>0 the function is genuinely ascending.If f'
Equation for linear approximation?
The general equation for a linear approximation is f(x) ≈ f(x0) + f'(x0)(x-x0) where f(x0) is the value of the function at x0 and f'(x0) is the derivative at x0. This describes a tangent line used to approximate the function. In higher order functions, the same concept can be applied. f(x,y) ≈ f(x0,y0) + fx(x0,y0)(x-x0) + fy(x0,y0)(y-y0) where f(x0,y0) is the value of the function at (x0,y0), fx(x0,y0) is the partial derivative with respect to x at (x0,y0), and fy(x0,y0) is the partial derivative with respect to y at (x0,y0). This describes a tangent plane used to approximate a surface.
How do you solve to find slope?
The answer depends on the nature of the function that defines the curve whose slope you want. If the function f(x) is differentiable, its slope is f'(x) = df(x)/dx and the value of the slope at a point when x = x0 is f'(x0), obtained by substituting x0 for x in f'(x).
What causes the graph of a rational function to have a vertical asymptote?
When your input variable causes your denominator to equal zero. * * * * * A rational function of a variable, x is of the form f(x)/g(x), the ratio of two functions of x. Suppose g(x) has a zero at x = x0. That is, g(x0) = 0. If f(x0) is not also equal to 0 then at x = x0 the rational function would involve division by 0. But division by 0 is not defined. Depending on whether the signs of f(x) and g(x) are the same or different, as x approaches x0 the ratio become increasingly large, or small. These "infinitely" large or small values are the asymptotes of the rational function at x = x0. If f(x0) = 0, you may or may not have an asymptote - depending on the first derivatives of the two functions.
How do you find whether a tangent line is vertical to a function?
A tangent line is NEVER vertical to a function. It is vertical to the normal to the function - which is as far from vertical as you can get!The graph of a function, f(x) can have a tangent at a point. Let's call the point (x0,f(x0)). If f'(x) goes to positive infinity or f'(x) goes to negative infinity as x approaches x0 then f(x) has a vertical tangent at that point.
What is the answer to Evaluate x1 - x-1 plus x0 for x equals 2?
shut up and do your hw
How many x intercepts can a quadratic function have?
For a quadratic function, there is one minimum/maximum (the proof requires calculus) and also it is either always convex or concave (prove is also calculus) it is continuous every where, hence, it can have a maximum of 2 roots. Graph it. If there is more than 2 roots, by Intermediate Value Theorem, it cannot be convex/concave everywhere. It will HAVE to have two intervals of increasing or decreasing. It can be easily proven that given any quadratic function f(x), if x = x0 is a minimum/maximum, and x=a != x0 is a root, then 2x0-a is also a root. It is still true that a = x0 as 2x0-x0=x0 implying it is the only root. But the concept of min/max requires Calculus to prove existence. So, this is Calculus, not algebra.
What is Newton raphson's method in r programing?
It's a method used in Numerical Analysis to find increasingly more accurate solutions to the roots of an equation. x1 = x0 - f(x0)/f'(x0) where f'(x0) is the derivative of f(x0)
What is 10x0 equals?
so 10 x0 equals 0 people its times and x is diffrent to plus.
What is the correct procedure for epsilon-delta proofs in Calculus?
A function f(x), of a variable x, is said to have a limiting value of f(xo) as x approaches x0 if, given any value of epsilon, however small, it is possible to find a value delta such that |f(x) - f(x0)| < epsilon for all x such that |x - x0| < delta.The second inequality can be one-sided.
The measure of the supplement of an angle exceeds twice the measure of the supplement of the complemant of the angle by 40?
The answer is -13 1/3ohere is the detailed calculation for the problem:Let x0 be the angle, then;(180 - x0) - 2[180 - (90 - x0)] =40(180 -x0) - 2[90+x0]=40180 -x0 - 180 - 2x0=40-3x0=40hencex0= -13 1/3oAny comments are welcome
what is 4E8374832E374684237eX72372+399x0+273646728-1888?
0! You said x0! anything x0=0!
