0
9r = 3r + 6
subtract 3r from both sides
6r = 6
divide both sides by 6
r=1 ■
Wiki User
∙ 14y ago
Add your answer:
Earn +20 pts
How do you work out the problem 9r equals 3r plus 6?
9r = 3r+6 Subtract 3r from both sides: 6r = 6 Divide both sides by 6 to find the value of r: r = 1
3r plus 6-6 equals 2r-12-6?
No, it's simply 3r, because multiplication (r multiplied by 3) comes first in the order of operations.
Simplify -5r-9s plus 9r plus 3s-6?
You have to combine equal terms. -5r-9s+9r+3s-6 = -5r+9r-9s+3s-6 = 4r-6s-6
5r2 plus 12r equals -4r2-4?
To answer a quadratic like this, st everything equal to zero. 5r^2+12r=-4r^2-4 9r^2+12r+4=0 Ask yourself what two numbers add to get 12 that multiply to get 9*4=36 1*36 no 2*18 no 3*12 no 4*9 no 6*6 yes (3r+2)(3r+2) The first and last multiply to get 6 and the outside and inside multiply to get 6. That's (3r+)^2
-7p plus 5r-6p plus 3r?
-7p + 5r - 6p + 3r = -7p - 6p + 5r + 3r = -(7 + 6)p + (5 + 3)r = -13p + 8r
What does 14r plus 6 multiply 3r subtract 2?
It does nothing. It has no capacity for doing anything. 14r + 6 * 3r - 2 = 14r + 18r - 2 = 32r - 2
How do you factorise this 6p plus 12q plus 18r?
6p + 12q + 18r = 6 (p + 2q + 3r)
R plus 3 plus 2r equals - 21?
r+3+2r=21 to solver this equation you have to first simplify then solve. you have to combine same variables. 3r+3=21 -3 -3 you subtract three to get r by itself (3r=18)/3 you divide by three to get r by itself Answer r=6
What is 5r plus 7 equals 13 plus 2r plus 3r?
1)5r+7=13+2r+3r 2)5r+7=13+5r 3)5r's cancel 7=13 4)Subtract thirteen on both sides 7 =13 -13 -13 5)Answer is no solution because -6 doesn't equal to 0. -6=0 NO SOLUTION!!! Have fun with math!
How do i solve -3r 3r-6(7 7r)-7(4-7r)?
how do i solve -3r+3r=-6(7+7r)-7(4-7r)
2 plus 5 plus 3 equals 132 3 plus 6 plus 4 equals 380 4 plus 2 plus 7 equals 63 6 plus 3 plus 6 equals 228 8 plus 5 plus 2 equals?
No.
Which pair of values is the solution to the system of equations below r plus 2t equals -3 and 3r-4t equals -9?
r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)
