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14r + 6 * 3r - 2 = 14r + 18r - 2 = 32r - 2
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What is r in this equation and how do you do it minus 5 equals 7 plus 3r?
-5 = 7 + 3r | subtract 7 -12 = 3r | divide by 3 -4 = r
What is the answer of 9r equals 3r plus 6?
9r = 3r + 6 subtract 3r from both sides 6r = 6 divide both sides by 6 r=1 ■
How do you factor this problem 18r squared - 84r plus 18 and 2c squared - 17c -9?
6(3r^2 - 14r + 3) and (2c + 1)(c - 9)
What is the answer to 3r plus 3r plus 2t?
3r + 3r + 2t = 6r + 2t
How do you work out the problem 9r equals 3r plus 6?
9r = 3r+6 Subtract 3r from both sides: 6r = 6 Divide both sides by 6 to find the value of r: r = 1
13r plus 10 equals 5r-46?
3r+10=5r-46 --> add 46 to both sides 3r+10+46=5r-46+46 3r+56=5r --> subtract 3r from both sides 3r+56-3r=5r-3r 56=2r --> divide both sides by 2 56/2=2r/2 28=r
Multiply r2 plus 7r plus 10 over 3 by 3r-30 over r2-5r-50?
r+2
Can r plus 2r - 3r be simplified?
5
How do you factor 9r squared minus 12r plus 4?
(3r - 2)(3r - 2) or (3r - 2) squared.
-7p plus 5r-6p plus 3r?
-7p + 5r - 6p + 3r = -7p - 6p + 5r + 3r = -(7 + 6)p + (5 + 3)r = -13p + 8r
How do you solve the equation 17 equals 13-3r?
17 = 13 - 3r Subtract 13 from bith sides: 4 = -3r Divide both sides by -3 : -4/3 = r or r = -1.3...
Solve 4r plus 3 equals 3r- 2 for r?
4r +3 = 3r-2 r + 3=-2 r=-5 basically collect terms so that you get one coefficient of r (in this case 4r on one side and 3r on the other. To get the three r over to the other side you subtract 3r on both sides.) Then r+ 3=-2, so that's simple algebraic manipulation.
