3r - 9r = 18 wright equaton -6r = 18 combine like terms r = -3 solve
4r +3 = 3r-2 r + 3=-2 r=-5 basically collect terms so that you get one coefficient of r (in this case 4r on one side and 3r on the other. To get the three r over to the other side you subtract 3r on both sides.) Then r+ 3=-2, so that's simple algebraic manipulation.
3R is Recycle,Reduce and Reuse
r - 10 + 100 - 3r = -2r + 90
(3r + 2)(r - 5)
7r = 3r - 527r (- 3r) = 3r - 52 (- 3r)4r = - 524r / 4 = -52 / 4r = -13
17 = 13 - 3r Subtract 13 from bith sides: 4 = -3r Divide both sides by -3 : -4/3 = r or r = -1.3...
3r - 9r = 18 wright equaton -6r = 18 combine like terms r = -3 solve
Oh honey, "3r 12" doesn't quite make sense. I think you might have mixed up your math lingo there. If you're looking to solve an equation involving "3r" and "12," we need a bit more information to get to the bottom of it. Just remember, math is like a recipe - you gotta have all the right ingredients to make it work.
3r + 3r + 2t = 6r + 2t
5
4r +3 = 3r-2 r + 3=-2 r=-5 basically collect terms so that you get one coefficient of r (in this case 4r on one side and 3r on the other. To get the three r over to the other side you subtract 3r on both sides.) Then r+ 3=-2, so that's simple algebraic manipulation.
3R is Recycle,Reduce and Reuse
(3r - 2)(3r - 2) or (3r - 2) squared.
3r+10=5r-46 --> add 46 to both sides 3r+10+46=5r-46+46 3r+56=5r --> subtract 3r from both sides 3r+56-3r=5r-3r 56=2r --> divide both sides by 2 56/2=2r/2 28=r
(3r - 8)(3r - 8)
Exactly as in the question: 3r-1