Do you mean: x+y = -1 and 4x+y = -10
If so then: x = -3 and y = 2
7x - 3y = 37 2x - y = 12 You can eliminate y by multiplying both sides of equation 2 by minus 3 and then add: 7x - 3y = 37 -6x + 3y = -36 x = 1 substitute x =1 into either equation and solve y 2(1) -y =12 -y = 10 y = -10
You could multiply the first equation by 3 and the second by -5 and eliminate the x... OR you could multiply the first equation by 7 and the second by 10 and eliminate the y. Either way works.
We can work this out by using the equation 150x10.1500
You can write an equation, using the definition of "average", then solve it. The equation would look like this:"the average of a and -5" is 10 (a - 5) / 2 = 10
I'll assume the simplified case of two equations, with two variables each. Some of the methods can be extended to more complicated cases.Substitution: Solve for one variable in one equation, replace it in the other equation.Setting two quantities equal: For example, if 5x + 3y = 10, and 5x - 2y = 0, solve each equation for "5x", and set the two equal, with the result: 10 - 3y = 2y.Addition/subtraction: Add or subtract one equation (or a multiple of one equation) to the other. In the previous example, if you subtract the second equation from the first, you get an equation that doesn't contain x.In any of these cases, after solving for a single variable, replace in one of the original equations to get the other variable.
It is x^2 - 20x + 100 = 0.
42
The LCM of 6 and 10 is 30.
10
5x = 10 - 20 gives 5x = -10 so that x = -10/5 = -2. Substitute this value in the second equation:-5*-2 + y = 9that is 10 + y = 9so that y = -1
Using proper grammer make question understandable is yes?
12